The pOH of a solution is related to the concentration of hydroxide ions in a solution. Also, it is related to the pH of the solution since the sum of pOH and pH is equal to 14. We can use this relation to solve this problem. We do as follows:
pH = -log[<span>1.7 × 10−9 M</span>] = 8.8
pOH + pH = 14
pOH + 8.8 = 14
pOH = 5.2
<span>HCl<span>(aq)</span>+NaOH<span>(aq)</span>→NaCl<span>(aq)</span>+<span>H2</span>O<span>(l)</span></span>
As you can see here, one mole of acid neutralizes one mole of base.
We use the concentration equation, which states that,
<span>c=<span>nv</span></span>
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<span>
<span>
n is the number of moles
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v is the volume of solution
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</span>
</span>
Rearranging for moles, we get,
<span>n=c⋅v</span>
So, we have:
<span><span>n<span>NaOH</span></span>=0.1 M⋅0.05 L</span>
<span>=0.005 mol</span>
Since one mole of acid neutralizes one mole of base, then we must have: <span><span>n<span>HCl</span></span>=<span>n<span>NaOH</span></span></span>.
And so,
<span><span>c<span>HCl</span></span>=<span><span>n<span>HCl</span></span><span>v<span>HCl</span></span></span></span>
<span>=<span><span>0.005 mol</span><span>0.03 L</span></span></span>
<span>≈0.17 <span>M</span></span>
Answer:
ik ppl sy no links but https://courses.lumenlearning.com/cheminter/chapter/the-ph-scale/
Explanation: it should help you
It would be C, because Ionic bonds have to deal with valence electrons ( the outer shell ones)
