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Rudik [331]
3 years ago
12

How many grams of oxygen are required to burn 3.01 x 10^23 propane molecules?

Chemistry
1 answer:
Tema [17]3 years ago
3 0
That’s some hard stuff what grade are you in im going to find the answer really fast hold on
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What does the group number of A elements in the A/B numbering system)
Ivanshal [37]

Answer:

All elements in the same A group will have the same number of

valence electrons.

Explanation:

Group A has 1 valence electrons.

4 0
3 years ago
g modenr vacuum pumps make it easy to attain pressures of the order of in the laboratory. at a preasusure of 6.75 atm and an ord
Ratling [72]

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

7 0
3 years ago
Answer the 4 questions pls
Vedmedyk [2.9K]
A b A or just the person above me said
7 0
3 years ago
Read 2 more answers
What mass of AI2O3 forms, knowing the molar mass of Al2O3 is 102 g/mol ?
TiliK225 [7]

Question

What mass of Al₂O₃ form is produced if 25.00 g of aluminum (al) is reacted completely?, knowing the molar mass of Al₂O₃ is 102 g/mol?

Atomic mass of Al =27 and O = 16

The molar mass of Al₂O₃ = 102.

Mass of aluminium in 102 g of Al₂O₃ = 54 g

54 g Al => 102 g Al₂O₃

25g Al => x g Al₂O₃

x = 25*102/54 = 47.2 g Al₂O₃

To solve more questions on molar mass check here:

brainly.com/question/21334167

3 0
1 year ago
What is the bond for PbCl4
LuckyWell [14K]

Answer:

The bond is covalent.

Explanation:

3 0
3 years ago
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