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3 years ago

9.5289 x 10^5 in^3 to cubic decimeters. Show the work please

Chemistry

1 answer:

salantis [7]3 years ago

5 0

We know that 1 in = 0.254 decimeters

9.5289 x 10^5 in^3 *( 0.254 decimeters/1.00 in)^3

= 15615.06941 cubic decimeters

= 1.56 *10^4 cubic decimeters

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You have a cup of tea (250 ml) that is 375 K which is too hot to drink. It needs to be cooled to 350 K before you can drink it.

S_A_V [24]

Answer:

The hot tea should transfer 25.63 kJ the surroundings to cool the tea.

Explanation:

To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat has to be transferred from the tea to the surroundings to cool the tea (Q = ??? J).

m is the mass of the hot tea (m = dV = (1.0 g/mL)(250 mL) = 250 g), suppose the density of water is the density of tea.

c is the specific heat of the hot tea (c = 4.10 J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 350 K - 375 K = -25°C).

∴ Q = m.c.ΔT = (250 g)(4.10 J/°C.g)(-25°C)) = - 25630 J = - 25.63 kJ.

So, the hot tea should transfer 25.63 kJ the surroundings to cool the tea.

4 0

3 years ago

10 uses of metals in daily life

Lesechka [4]

Answer:For jewellery and ornaments, gold, platinum and silver are being used.

For building purposes, iron and steel can be used.Iron and aluminium are used as utensils.

The thermometer uses mercury and helps to monitor the temperature.

The insulation wires are made of aluminium.

Aluminium foils are being used as wrappers for food.In sweets, a silver foil is being used.

To avoid rusting, zinc is used for galvanizing.In vehicles, iron is being used.

For making cable wires, copper is being used.

Explanation:

6 0

2 years ago

Read 2 more answers

Consider the dissolution of 1.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreas

-BARSIC- [3]

Answer:

The quantity of heat lost by the surroundings is 258,5J

Explanation:

The dissolution of salt XY is endothermic because the water temperature decreased.

The total heat consumed by the dissolution process is:

4,184 J/g°C × (75,0 + 1,50 g) × 0,93°C = 297,7 J

This heat is consumed by the calorimeter and by the surroundings.

The heat consumed by the calorimeter is:

42,2 J/°C × (0,93°C) = 39,2 J

That means that the quantity of heat lost by the surroundings is:

297,7J - 39,2J = 258,5 J

I hope it helps!

8 0

3 years ago

Which of the following is NOT a physical property?

ICE Princess25 [194]

Answer:

reactivity is NOT a physical property

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3 years ago

A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system

AleksAgata [21]

To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

$-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w$

Clearing the specific heat of the unknown substance:

$c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}$

$c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}$

6 0

3 years ago