To Find :
The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s.
Solution :
The horizontal range of a projectile is given by :
( Here, g is acceleration due to gravity = 10 m/s² )
Putting all value in above equation :
Therefore, the horizontal range of projectile is 80 m.
Elements are represented by their symbols with the first letter capitalized and the rest in lowercase. Copper is represented by Cu and Bromine is represented by Br. When combined to for a compound, the format of the symbols remain. Hence, the correct format would be CuBr.
Thus, the answer is C: CuBr<span>.</span><span />
We have get the mass of gaseous water after evaporation in a closed container.
The mass of water vapor after evaporation is 5 grams.
In closed container, there is no exchange in mass from system to surrounding, only heat may exchange. The number of moles of water vapour remains unchanged as 5 gram water is heated in closed container.
Due to heating, liquid water gets evaporated and intermolecular distance between water molecules increases in gaseous state than liquid state and intermolecuar force of attraction decreases.
Randomness of molecules increases in gaseous state than liquid state.
Answer:
I believe the answer is B.
Explanation:
I have never heard of it meaning the coldest point in outer space or freezing point of "pure" water at sea level. As for C, substances have a different points where the molecules stop moving. So the answer that makes the most sense is B.
Answer:
The temperature of the system once the equilibrium has been reached = 372.55K
Explanation:
Heat capacity of gold = 129 J/Kg*c.
Heat capacity of water
4,184 J/Kg*c.
Mass of gold = 75g = 0.075Kg
Mass of water = 200g = 0.2Kg
From conservation of energy
m1×C1×(t11 - t2) = m2×C2×(t2- t21)
Substituting we have
0.075 × 129×(1000-t2) = 0.2× 4184×( t2 -300) =solving for t2, we have
933.55×t2 = 347790
or t2 = 372.55K
The temperature of the system once the equilibrium has been reached = 372.55K
