Answer:
T₂ = 464.75 K
Explanation:
Given data:
Initial Temperature = 398.15 K
Pressure = 248 torr (constant)
Initial Volume = 275 mL (275/1000 = 0.275 L)
Final volume = 0.321 L
Final temperature = ?
Solution:
V₁/T₁ = V₂/T₂
T₂ = V₂ T₁ / V₁
T₂ = 0.321 L × 398.15 K / 0.275 L
T₂ = 127.81 L.K / 0.275 L
T₂ = 464.75 K
Honey in essence is a Mixture of biologically infused chemicals from the pollen and bee fertilization.<span>Honey contains a number of enzymes, including invertase, which converts sucrose to </span>glucose<span> and fructose; amylase, which breaks </span>starch<span> down into smaller units; </span>glucose oxidase<span>, which converts </span>glucose<span>to </span>gluconolactone.
I’m pretty sure they are, but it depends on which acids. Some acids have a really high or low ph that can burn through items, like our stomach acid. Instead, something with a high melting point would be used.
Answer:
Distribution coefficient: 4.79
Explanation:
Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:
Distribution coefficient: Concentration in chloroform / Concentration in Water
<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>
<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>
<em />
Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL
<h3>Distribution coefficient: 4.79</h3>
Count the atoms of each element in the reactants and the products. Use coefficients; place them in front of the compounds as needed.