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lidiya [134]
3 years ago
11

Which of the following statements is false about drawing Lewis structures?

Chemistry
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

c. N, P, and As can sometimes share more than 8 e-

Explanation:

Lewis structures are diagrams that show the valence electrons of atoms within a molecule. Valence electrons play a major role while drawing Lewis structures as only valence electrons can be shared with another molecule to form a bond.

N, P, and As can not share more than 8 e- because they have less valence electrons in their outer shell. N has only one valence electron, P and As has only 5 valence electrons so they can not share more than their valence electrons.

Hence, the correct answer is "c. N, P, and As can sometimes share more than 8 e-".

You might be interested in
Which nonmetal has the greatest potential to be oxidized
Tasya [4]

Answer:

Hydrogen

Explanation:

A reducing agent is a substance which gives up its electrons to become oxidized. Generally, metals are oxidized (reducing agents) while non-metals are reduced (oxidizing agents).

However, hydrogen which is a non-metal is usually oxidized in the presence of stronger oxidizing non-metals such as fluorine and oxygen.

Hydrogen thus, acts as a reducing agent by giving up its electrons to become oxidized. Even though among all non-metals, Hydrogen has the greatest potential to be oxidized, it is a poor reducing agent compared to reactive metals.

7 0
4 years ago
What would be the best source of data for you current diet?
AlexFokin [52]
A diet rich in vegetables and fruits can lower blood pressure such as eating healthy
5 0
3 years ago
Assume that Aluminum and Silver Sulfide are the starting substances (reactants) in the reaction: a. Write a balanced chemical eq
Naddik [55]

Answer:

Check Explanation

Explanation:

a) The balanced chemical reaction between Aluminium and Silver Sulfide is represented below

2Al + 3Ag₂S → Al₂S₃ + 6Ag

Aluminium displaces Silver from Silver sulfide because it is higher than Silver in the electrochemical series.

b) Names of the products from this reaction

Ag is called Silver metal. Free Silver metal.

Al₂S₃ is called Aluminium Sulfide.

c) This reaction is a single-displacement reaction because an element directly displaces and replaces another element in a compound.

It is also a redox reaction (reduction-oxidation reaction) because there are species being oxidized and reduced simultaneously!

d) Yes, this reaction is an oxidation-reduction (redox) reaction because there are species being oxidized and reduced simultaneously!

e) The specie that is being oxidized is said to undergo oxidation. And oxidation is defined as the loss of electrons, thereby leading to an increase in oxidation number.

In this reaction, it is evident that Aluminium undergoes oxidation as its oxidation number increases from 0 in the free state to +3 when it displaces Silver and becomes Aluminium sulfide.

Al → Al³⁺

0 → +3 (Oxidation)

The specie that is being reduced is said to undergo reduction. And reduction is defined as the gain of electrons, thereby leading to a decrease in oxidation number.

In this reaction, it is evident that the silver ion undergoes reduction as its oxidation number decreases from +1 in the Silver Sulfide compound to 0 when it is displaced and becomes Silver in free state.

Ag⁺ → Ag

+1 → 0 (Reduction)

The reducing agent is the specie that brings about reduction. Since Silver ion in Silver sulfide is reduced, Aluminium is the reducing agent that initiates the reduction process.

The oxidation agent is the specie that brings about oxidation. Since, Aluminium is the specie that undergoes oxidation, the oxidizing agent is the Silver Sulfide that brings about the oxidation.

Hope this Helps!!!

6 0
3 years ago
Consider a series of molecules in which the C atom is bonded to atoms of second-period elements: C-O, C-F, C-N, C-C, and C-B. Pl
Sati [7]

Answer:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Explanation:

As we move along to the <u>right in the same period, the electronegativity</u> and <u>the effective nuclear charge values are higher.</u>

The tendency is that <em>the higher these values are, the shorter the bonds will be</em>.

With that information in mind, and looking at the periodic table, the order would be:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Where the C-F bond is the shortest among them.

8 0
3 years ago
I need help so please help me
Kay [80]

Answer:b

Explanation:

I honestly don’t know if this I right but that would be my guess

3 0
3 years ago
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