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3 years ago

Methyl phenolphthalein and litmus

Chemistry

2 answers:

aev [14]3 years ago

8 0

Answer:

Types of indicators which show if the solution is an acid , alkali or a natural

Explanation:

You add one of two drops of the indicator into a solution and then it would be in a scale from red to purple and this is called a PH scale which shows if it's an acid, alkali or a natural solution red being a strong acid with the PH number of one , green being a natural solution with the PH number of 7 and an alkali being purple with the PH number of 14

Hope this helps :)

Butoxors [25]3 years ago

4 0

Answer:

Both are the indicators which helps to identity the acid and base

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dimulka [17.4K]

Answer:

Explanation:

I just learned all this in chemistry too lol

got 100 on the test last week so its good

6 0

3 years ago

When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from ______ C to 87 C.

harkovskaia [24]

V1/T1=V2/T2
(15.5)/(360K)=(3.6)/(T2)
T2=83.61290K
T2=-189.3871 degrees Celsius

5 0

3 years ago

Read 2 more answers

A drought hits the habitat of a semi-aquatic bird population. All ponds dry up, and fish populations decline. There are two grou

alexandr1967 [171]

Answer:

The population of the long-legged birds decreases.

Explanation:

The population of the short-legged birds increases whereas the population of long-legged birds decreases due to availability of food in that environment. The long-legged birds feed on fish whose population decreases due to drought conditions so the population of long-legged birds also decreases while on the other hand, the population of short-legged birds increases or remain the same because they feed on the insects and the insects are available in large amount and less affected by the drought conditions.

4 0

3 years ago

What mass of gold is produced when 23.8 a of current are passed through a gold solution for 36.0 min ?

SVETLANKA909090 [29]

Answer:-

Solution:- The equation for the conversion of gold ions to gold metal is as follows:

$Au^3^+(aq)+3e^-\rightarrow Au(s)$

From this equation, 1 mol of Gold metal is deposited by 3 mole of electrons.

We know that one mol of electron carries one Faraday that is 96500 Coulombs.

So. 3 moles of electrons would be = 3(96500) = 289500 Coulombs

We could calculate the total Coulombs by using the formula:

q = i*t

where, q is the charge in coulombs, i is the current in ampere and t is time in seconds.

q = $23.8 ampere*36.0 min(\frac{60 sec}{1 min})$

q = 51408 ampere per second

Since, 1 ampere per second = 1 coulomb

So, 51408 ampere per second is same as 51408 coulombs.

Let's use this value of q and the info from balanced equation and molar mass(196.967 g epr mol) of gold to calculate the mass of it being deposited while the current is passed as:

$51408 coulomb(\frac{1 mol Au}{289500 coulombs})(\frac{196.967 g}{1 mol})$

= 35.0 g Au

So, 35.0 g of gold are deposited on passing 23.8 ampere of current for 36.0 min to a gold solution.

7 0

3 years ago

Clch2ch2chclch2ch3 +NaI (1.0 equiv)acetone

Margaret [11]

No thanks. I dont buy drugs

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3 years ago