Question

10) What is the energy of a photon whose frequency is 2.7 X 1014 Hz?

Answer 1

Answer: c

Explanation:

$E=hf$

h = constant

f = frequency

$E=(6.626x10^-^3^4J/s)(2.7x10^1^4Hz)\\E=1.78902x 10^-^1^9$

moving the point 1 number to the right, and rounding up, leaves us with;

$E=17.9x 10^-^2^0$