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3 years ago

One card is randomly selected from a deck of cards. find the odds against drawing a blackblack fivefive.

1 answer:

6 0

Since there are 2 black suites and there are 26 (1/2) black cards in a deck, and there is 1 five per suite, there are 2 black fives. Therefore, since there are 52 cards in a deck, there is a 2/52 you draw a black 5. To find the odds against that, we get 1-2/52=52/52-2/52=50/52 due to that we want to find the probability of not drawing a black 5 so we subtract the chances of getting that from the equation

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Tyler goes running every 6 days. Steve goes running every 9 days. If they both ran today, in how many days will they run togethe

sergejj [24]

5 runs more. 5 runs more

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3 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

A triangle has two sides of lengths 7 and 12 what value could the third side be?

Gennadij [26K]

$a,b,c- sides\ of \ triangle\\\\Conditions\ for\ triangle \existing\\\\a+b>c\\b+c>a\\a+c>b\\\\\ a=7\\b=12\\\\1.\\7+12>c\ \ \ -->c7\ \ \ -->c>7-12\ \ c>\ -->-5\\3.\\7+c>12\ \ -->c>12-7\ \ -->c>5\\\\Product \ of\ all\ conditions\\ c\in(5,19)$

7 0

3 years ago

What is the nth term of a geometric sequence that has a common ratio of 6 and 24 as the third term

Ivanshal [37]

The common ratio r is 6, while the third term (ar²) is 24.
Nth term in a GP is given by the formula ar^n-1, thus the third term is ar²
ar²= 24
thus, a × 36 = 24
a =24/36
The ninth term is given by ar^8
= (24/36)× 6^8
= 1119744.

4 0

3 years ago

2/7, 3/4, 2/3. Arrange it in ascending order<br>

MariettaO [177]

Answer:

2,7 2,3 3/4

Step-by-step explanation:

2,7 = 0.29 2,3 = 0.67 3/4 = 0.75

6 0

3 years ago

Read 2 more answers