Answer:
The answer to your question is V2 = 867.3 mL
Explanation:
Data
Volume 1 = V1 = 400 ml
Temperature 1 = T1 = 22°C
Pressure 1 = P1 = 760 mmHg
Volume 2 = V2 = ?
Temperature 2 = T2 = 30°C
Pressure 2 = P2 = 360 mmHg
Process
1.- Convert Celsius to Kelvin
T1 = 22 + 273 = 295°K
T2 = 30 + 273 = 303°K
2.- Use the Combined gas law
P1V1/T1 = P2V2/T2
- Solve for V2
V2 = P1V1T2 / T1P2
- Substitution
V2 = (760 x 400 x 303) / (295 x 360)
- Simplification
V2 = 92112000 / 106200
-Result
V2 = 867.3 mL
Answer:
See explanation below
Explanation:
In this reaction we have the ethyl acetoacetate which is reacting with 2 eq of sodium etoxide. The sodium etoxide is a base and it usually behaves as a nucleophyle of many reactions. Therefore, it will atract all the acidics protons in a molecule.
In the case of the ethyl acetoacetate, the protons that are in the methylene group (CH3 - CO - CH2 - COOCH2CH3) are the more acidic protons, therefore the etoxide will substract these protons instead of the protons of the methyl groups. This is because those hydrogens (in the methylene group) are between two carbonile groups, which make them more available and acidic for any reaction. As we have 2 equivalents of etoxide, means that it will substract both of the hydrogen atoms there, and then, reacts with the Br - CH2CH2 - Br and form a product of an aldolic condensation.
The mechanism of this reaction to reach X is shown in the attached picture.
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Answer:
Corresponds to a covalent compound.
Explanation:
Both Boron and Fluorine are nonmetals, forming a covalent bond, the result of which is the boron trifluoride compound (BF3). This is a highly toxic gas.
It is synthesized by the reaction between hydrogen fluoride and boron oxide:
B2O3 + 6 HF → 2 BF3 + 3 H2O