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alina1380 [7]
3 years ago
11

Suppose you are working in a chemistry lab and trying to make a solution of a substance called Sodium Chloride (which is a solid

) of a definite amount and volume. Mention which lab apparatuses you would need to complete your work perfectly.
Chemistry
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer

Explanation:

The lab apparatus that would be needed to prepare a solution of sodium chloride would be <em>a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer.</em>

The weighing balance would be used to weigh out the required amount of sodium chloride. The beaker or flask would be placed on the weighing balance and its weight zeroed. The spatula would then be sued to take out the sodium chloride from its container into the beaker till the required amount is reached. The measuring cylinder would then be used to measure out the required volume of water which would be added to the salt in the beaker. The stirrer would then be used to stir the mixture in order for the salt to dissolve.

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You wish to prepare a tape-casting slip containing 50 vol% Al2O3 and 50 vol% polyvinyl butyral (PVB) binder. If the density of A
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<u>Answer:</u> The mass of PVB required to produce 1000 grams of tape is 213.4 grams

<u>Explanation:</u>

To calculate the mass of aluminium oxide, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}       .......(1)

  • <u>For Al_2O_3</u>

We are given:

50% (v/v) of Al_2O_3

This means that 50 mL of aluminium oxide is present in 100 mL of tape

Calculating the mass of aluminium oxide by using equation 1:

Density of aluminium oxide = 3.98 g/cm^3

Volume of aluminium oxide = 50mL=50cm^3     (Conversion factor:  1mL=1cm^3 )

Putting values in equation 1, we get:

3.98g/cm^3=\frac{\text{Mass of aluminium oxide}}{50cm^3}\\\\\text{Mass of aluminium oxide}=(3.98g/cm^3\times 50cm^3)=199g

Mass of aluminium oxide = 199 g

  • <u>For PVB:</u>

We are given:

50% (v/v) of PVB

This means that 50 mL of PVB is present in 100 mL of tape

Calculating the mass of PVB by using equation 1:

Density of PVB = 1.08 g/cm^3

Volume of PVB = 50mL=50cm^3

Putting values in equation 1, we get:

1.08g/cm^3=\frac{\text{Mass of PVB}}{50cm^3}\\\\\text{Mass of PVB}=(1.08g/cm^3\times 50cm^3)=54g

Mass of PVB = 54 g

Mass of tape = Mass of aluminium oxide + mass of PVB

Mass of tape = [199 + 54] g = 253 g

To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:

When 253 grams of tape is made, the mass of PVB required is 54 g

So, when 1000 grams of tape is made, the mass of PVB required will be = \frac{54}{253}\times 1000=213.4g

Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams

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