It should be C. If the object is denser than the fluid, it will sink. If it isn't, it will float
My guess would be about 10 years because stars are hot balls of light that are reflections from years ago so it would most likely take awhile
Answer:
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.
Explanation:
From coulomb's law, F = Eq
Thus,
F = E₁q₁
F = E₂q₂
Then
E₂q₂ = E₁q₁
![E_2 = \frac{E_1q_1}{q_2}](https://tex.z-dn.net/?f=E_2%20%3D%20%5Cfrac%7BE_1q_1%7D%7Bq_2%7D)
where;
E₂ is the external electric field due to second test charge = ?
E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C
q₁ is the first test charge = 13 mC
q₂ is the second test charge = 23 mC
Substitute in these values in the equation above and calculate E₂.
![E_2 = \frac{4*10^6*13}{23} = 2.26 *10^6 \ N/C](https://tex.z-dn.net/?f=E_2%20%3D%20%5Cfrac%7B4%2A10%5E6%2A13%7D%7B23%7D%20%3D%202.26%20%2A10%5E6%20%5C%20N%2FC)
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.
However, the direction of the external field is still to the right.
The values of t are <u>4.643 second</u> for the function ![H(t)=-16t^2+73t+6](https://tex.z-dn.net/?f=H%28t%29%3D-16t%5E2%2B73t%2B6)
What is batter misses?
An out in baseball happens when the umpire declares a batter or baserunner out. A hitter or runner who is out is no longer able to score runs and must go back to the dugout until their subsequent turn at bat. The batting team's turn is over after three outs are recorded in a half-inning.
In order to signal an out, umpires typically make a fist with one hand and then flex that arm, either upward on pop flies or forward on regular plays at first base. To indicate a called strikeout, home plate umpires frequently use a "punch-out" action.When a batter is struck by a pitched ball without making a swing at it, it is referred to as a hit-by-pitch. He consequently gets first base.
We have been given that
s = 6 feet
v = 73 feet per second
Substituting these values in the formula ![H(t)=-16t^2+vt+s](https://tex.z-dn.net/?f=H%28t%29%3D-16t%5E2%2Bvt%2Bs)
![H(t)=-16t^2+73t+6](https://tex.z-dn.net/?f=H%28t%29%3D-16t%5E2%2B73t%2B6)
When the ball hits the ground, the height becomes zero. Thus, H(t)=0
![-16t^2+73t+6=0](https://tex.z-dn.net/?f=-16t%5E2%2B73t%2B6%3D0)
We solve the equation using quadratic formula ![x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting the values a=-16, b= 73, c=6
![t_{1,2}=\frac{-73 \pm \sqrt{(73)^2-4(-16)(6)}}{2(-16)}\\\Rightarrow t_{1,2}=\frac{-73 \pm \sqrt{5713}}{2(-16)}\\\Rightarrow t_{1,2}=-0.081, 4.643](https://tex.z-dn.net/?f=t_%7B1%2C2%7D%3D%5Cfrac%7B-73%20%5Cpm%20%5Csqrt%7B%2873%29%5E2-4%28-16%29%286%29%7D%7D%7B2%28-16%29%7D%5C%5C%5CRightarrow%20t_%7B1%2C2%7D%3D%5Cfrac%7B-73%20%5Cpm%20%5Csqrt%7B5713%7D%7D%7B2%28-16%29%7D%5C%5C%5CRightarrow%20t_%7B1%2C2%7D%3D-0.081%2C%204.643)
Learn more about the batter misses with the help of the given link:
brainly.com/question/19475098
#SPJ4
Absolutely none. Fish take food into their mouths and taste it. If they
like it, they swallow, if not they will spit it out. The color of the
flakes has no bearing on what the fish takes in and tastes in my
experience.
I hope this helps : )