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telo118 [61]
3 years ago
13

If a microwave oven produces electromagnetic waves with a frequency of 2.30 ghz, what is their wavelength?

Physics
2 answers:
77julia77 [94]3 years ago
8 0
\lambda = \frac{c}{\nu} = \frac{3 \cdot 10^8}{2.3 \cdot 10^9} = \frac{3}{23} \approx 0.130435 \approx 0.13 \ m.
vovikov84 [41]3 years ago
5 0

Answer: wavelength is 1.30 \times 10^8 nm.

The frequency of the microwave is, f = 2.30 GHz.

To Find frequency use the formula:

c=fλ

Where, c is the speed of electromagnetic wave or light. f is the frequency, and λ is the wavelength of light.

Rearranging, \lambda = \frac{c}{f}

Plug in the values,

\lambdam = \frac{3 \times 10^8 m/s}{2.30 GHz\frac{10^9 Hz}{1 GHz}}=0.130 m\frac{10^9 nm}{1 m} = 1.30 \times 10^8 nm.

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A football is kicked from the ground with a velocity of 38m/s at an angle of 40 degrees and eventually lands at the same height.
Anastasy [175]

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Converting back to direction and magnitude, we get \langle r,\theta \rangle=\langle \sqrt{29.11^2+24.23^2},tan^{-1}(\frac{29.11}{24.23}) \rangle = \langle 37.87,50.2^{\circ}\rangle

4 0
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What will happen if you drop a golf ball, a baseball, and a bowling ball at the same instant from the top of a tall building
V125BC [204]
Depending on the height of the building they can break due to impact on the floor.
8 0
3 years ago
Imagine that you have a 6.50 l gas tank and a 4.50 l gas tank. you need to fill one tank with oxygen and the other with acetylen
Margarita [4]
V₁(O2) = 6.50<span>  L                
</span>p₁(O2) = 155 atm          
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</span>p₂(acetylene) =?                             

According to Boyle–Mariotte law (At constant temperature and unchanged amount of gas, the product of pressure and volume is constant) we can compare two gases that have ideal behavior and the law can be usefully expressed as:

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7 0
3 years ago
If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st
liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0
3 years ago
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