Question

A wire, of length L = 4.1 mm, on a circuit board carries a current of I = 1.96 μA in the j direction. A nearby circuit element generates a magnetic field in the vicinity of the wire of B = Bxi + Byj + Bzk, where Bx = 4.9 G, By = 2.3 G, and Bz = 2.4 G.
a. Calculate the magnitude of the magnetic field B, in gauss, in the vicinity of the wire due to the circuit element.

Answer 1

Answer:

The magnitude of the magnetic field B is 5.921 T.

Explanation:

Given that,

Length = 4.1 mm

$B_{x}=4.9\ G$

$B_{y}=2.3\ G$

$B_{z}=2.4\ G$

Current $I = 1.96\ mu A$

We need to calculate the magnetic field

Using formula of magnetic field

$B=\sqrt{B_{x}^2+B_{y}^2+B_{z}^2}$

Put the value into the formula

$B=\sqrt{(4.9)^2+(2.3)^2+(2.4)^2}$

$B=5.921\ T$

Hence, The magnitude of the magnetic field B is 5.921 T.