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Ratling [72]
4 years ago
10

Give an example of two phase mixture and describe how you would separate the substances

Chemistry
1 answer:
Softa [21]4 years ago
7 0
<span>A two phase mixture is a mixture of two different substances. for example, a soft drink ( liquid and gas). to separate these two substances, you could heat the liquid and then capture the carbon dioxide.Also this is a question you need to answer for yourself there is many answers.</span>
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How many grams of oxygen are required to react with 12.0 grams of octane(C8H18) in the combustion of octane in gasoline?
solniwko [45]

Answer : 42 grams of oxygen are required.

Explanation :

Step 1 : Write balanced chemical equation.

The combustion reaction of octane with oxygen can be written as,

2 C_{8}H{18} (g)  + 25  O_{2} (g) \rightarrow 16 CO_{2} (g) +18  H_{2}O (g)

Step 2 : Find moles of octane.

The given mass of octane is 12 g

Molar mass of octane is 114.2 g/mol

The moles of octane are calculated as,

moles =\frac{grams}{MolarMass}  =\frac{12g}{114.2g/mol}  = 0.105 mol

We have 0.105 mol octane.

Step 3: Use mole ratio from balanced equation to find moles of O₂

The mole ratio of octane and O₂ is 2 : 25. Let us use this as a conversion factor.

0.105 mol C_{8}H_{18} \times\frac{25mol O_{2}}{2molC_{8}H_{18}}  = 1.31 mol

We have 1.31 mol O₂.

Step 4 : Convert moles of O₂ to grams.

The molar mass of O₂ is 32 g/mol.

The grams of O₂ can be calculated as,

1.31 mol O_{2} \times\frac{32g}{mol}  = 42 grams

42 grams of oxygen are required.

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3 years ago
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6 0
3 years ago
A 1.36 kg hammer at 22 ms what was the force generated by the hammer
podryga [215]
From the information given, the mass of the hammer seems to be 1.36 kg and the velocity by which it is wielded seems to be 22 m/s. The most suitable formula to be used here is : f = m × v where f is force, m is mass and v is velocity. f = m × v → f = 1.36 × 22 → f = 29.92 kg m/s Therefore the force generated by the hammer is 29.92 N ( kg m/s is the same as Newton)
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3 years ago
Find w12, the work done on the gas as it expands from state 1 to state 2.
dem82 [27]
The equation for work is
W = PdV
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