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KonstantinChe [14]

3 years ago

8

Find w12, the work done on the gas as it expands from state 1 to state 2.

1 answer:

dem82 [27]3 years ago

7 0

The equation for work is
W = PdV
and it is integrated and limits are the conditions of state 1 and state 2
If the gas is ideal and the expansion is isothermal, then P = nRT/V and the equation can be integrated with respect to V
If the process is adiabatic, the equation P1V1^g = PV^g can be used to substitue P in terms of conditions of State 1.

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Answer:

The net ionic equation for the given reaction :

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$3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)$ ...[1]

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Replacing $MnI_2(aq)$ , NaI and $Na_3PO_4(aq)$ in [1] by usig [2] [3] and [4]

$3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)$

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

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