44.99g H2O x (1 mol H2O / 18.02g H2O) x (6.022x10^23 molecules H2O / 1 mol H2O) = 1.503x10^24 molecules H2O
Answer:
188.5g of dextrose are needed
Explanation:
In Weight per volume percentage - %(w/v) -, the concentration is defined as the mass of solute in grams -In this case, dextrose-, in 100mL of solution.
As you want to prepare 725mL of a 26.0% (w/v) solution. you need:
725mL * (26g / 100mL) = 188.5g of solute =
<h3>188.5g of dextrose are needed</h3>
The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.
The order of reaction is equal sum of power of concentration of the each reactant present in the reaction that obeys the rate law . The order of individual reactant or species present in the rate law is equal to the power of the of concentration of the respective species or reactant .
Example : If rate law is given as,
rate = k![[a]^{4} [b]^{5}](https://tex.z-dn.net/?f=%5Ba%5D%5E%7B4%7D%20%5Bb%5D%5E%7B5%7D)
The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.
To learn more about order of reaction please click here
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Answer:

Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:

Best regards,
Water has a chemical formula of H2O. This means that for every 2 moles of hydrogen and 1 mole of oxygen, one mole of water will be formed.
Note that hydrogen gas and oxygen gas are both biatomic molecules.
(1) (182 mol H2) x (1 mol H2O/ 1 mol H2) = 182 mol H2O
(2) (86 mol O2) x (2 mol H2O / 1 mol O2) = 172 mol H2O
We choose the smaller number of the two as the answer to this item. Thus, the answer to this question is 172 mol of H2O can be formed out of the given quantities.