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Ne4ueva [31]
4 years ago
11

Can someone plz answer these questions for me?

Physics
1 answer:
krek1111 [17]4 years ago
5 0
Need more details, theres no picture or anything.

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bagirrra123 [75]
I don't really now a answer to the first one but this answer is for the second one: They provide a standardized system of classification for a language barrier.
8 0
4 years ago
(Will give brainliest) The values of the impulse and the time interval for various collisions are listed in the table. In which
igor_vitrenko [27]

Answer:

E) e

Explanation:

Impulse is equal to the product between the force applied (F) and the time interval of the collision (\Delta t):

I=F \Delta t

This means that we can calculate the force for each collision dividing the impulse by the time interval:

F=\frac{I}{\Delta t}

Let's apply the formula to each case:

A) F=\frac{10,000 kg m/s}{10^3 s}=10 N

B) F=\frac{1,000 kg m/s}{10^2 s}=10 N

C) F=\frac{100 kg m/s}{10^1 s}=10 N

D) F=\frac{10 kg m/s}{10^0 s}=10 N

E) F=\frac{1 kg m/s}{10^{-2} s}=100 N

Therefore, the force is the maximum for collision E).

5 0
4 years ago
Read 2 more answers
A ball is falling after rolling off a tall roof. The ball has
Rom4ik [11]
C.
Because it’s falling it has acceleration in the y direction. If you have acceleration, you usually also have velocity, and since kinetic energy is KE= Mv^2 you know you have it. It also has potential energy because it has some height to it, and PE= Mgh.
8 0
4 years ago
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What is sound reverberation?
otez555 [7]
Sound reverberation is created when sound or signal is reflected.
3 0
3 years ago
A disk with a uniform positive surface charge density lies in the x-y plane, centered on the origin. The disk contains 2.5 x 10-
allochka39001 [22]

Answer:

E=3 x 10^4 N/c

Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

E= (\sigma/\2epsilon_o)(1-z/ \sqrt(z^2+r^2))

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

ε_0= constant ( vacuum permitivity)

putting values we get

E= \frac{2.5\times10^{-6}}{2\times2.5\times10^{-6}}(1-\frac{0.15}{\sqrt{0.15^2+0.075^2} })

solving we get

E=30000 N/c

E=3 x 10^4 N/c

6 0
3 years ago
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