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Y_Kistochka [10]
3 years ago
10

What is the relation between centre of gravity and stability

Physics
1 answer:
maw [93]3 years ago
8 0

Explanation:

tilting it will raise the height of its center of gravity.

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You push on a box with a force of 300 N directly north. Another person pushes the box with a
tangare [24]

Answer:

resultant \\  \: F =  \sqrt{ {300}^{2} +  {600}^{2}  }  \\  =  \sqrt{450000}  \\  = 670.82 \: newtons

7 0
3 years ago
I will be so thankful if u answer correctly!!​
polet [3.4K]

(C) 200 N

Explanation:

The acceleration due to gravity on earth g_{E} is given by

g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}

where G = universal gravitational constant

\:\:\:\:\:\:\:\:\:\:\:\:M_{R} = mass of the earth

\:\:\:\:\:\:\:\:\:\:\:\:R_{E} = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity g_{K} is

g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}

\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}

\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}

or

g_{K} = (\dfrac{2}{9})\:g_{E}

If we multiply both sides by Superman's mass, we get his weights on both planets:

mg_{K} = (\dfrac{2}{9})\:(mg_{E})

W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N

3 0
3 years ago
https://brainly.com/question/add?entry=1642&task_content=Tania+was+asked+to+describe+the+relashio+of+electrity+and+magnetism
Nat2105 [25]

Answer:

wat

Explanation:

8 0
3 years ago
Draw a free body diagram of a person as their board accelerates them up into the sky. Be sure that, if a force is bigger than an
trasher [3.6K]

Answer:

I hope it helps.

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3 years ago
When does a skydiver achieve terminal velocity? when gravity equals air resistance when gravity is greater than air resistance w
ElenaW [278]

Answer:

when gravity equals air resistance

Explanation:

There are two forces acting on a skydiver falling down:

1) Gravity - this force acts downward, and it is constant during the whole fall, because its magnitude is given by

F=mg

where m is the mass of the skydiver and g the gravitational acceleration. Both quantities are constant, so the force of gravity is constant.

2) Air resistance - this force acts upward, and it is not constant: it is proportional to the velocity of the skydiver

F=kv

where k is a constant and v is the velocity. Therefore, as the skydiver falls down, its velocity increases and the air resistance increases as well.


The equation of forces for the skydiver is therefore:

mg-kv=ma

where a is the skydiver's acceleration. At the beginning of the fall, mg>kv, so the skydiver accelerates towards the ground. However, as he accelerates, the air resistance kv increases, till the moment at which air resistance becomes equal to gravity:

mg=kv

when this condition occurs, then the acceleration becomes zero, so the skydiver no longer accelerates and continues his fall at constant speed. This constant speed is called terminal velocity, and so it occurs when

gravity equals air resistance

3 0
3 years ago
Read 2 more answers
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