Answer:
The resistance of the aluminium wire is 0.541 ohms
Explanation:
Given:
Cross sectional area of the aluminum wire, A = 4.9 x 10-4 m2
Length of the wire, L = 10 km = 10,000 m
Resistance of the wire = (pL) / A
Where:
p is resistivity of aluminium wire = 2.65 x 10^-8 ohm-m
L is length of the wire
A is cross sectional area of the wire
Substitute these values and solve for resistance of the wire.
Resistance = (2.65 x 10^-8 x 10,000) / (4.9 x 10^-4)
Resistance = 0.541 ohms
Therefore, the resistance of the aluminium wire is 0.541 ohms
Answer:
0.0025 sec
Explanation:
Period = 1 / frequency = 1/400 = 0.0025 sec
<span>1.50 x 3.00 = V x 1.00 atm ( Boyle's law)
V = 1.50 x 3.00 / 1.00 = 4.50 L </span>
Answer:
0.480 seconds
Explanation:
The period is the time for 1 revolution. Writing a proportion:
14.4 s / 30.0 rev = t / 1 rev
t = 0.480 s
The period is 0.480 seconds.
The statement: “According to Faraday's law, voltage can be changed by moving magnets away from the coil of wire.”, is true. Any type of movements done (away, into or out, toward, rotation, etc.) on the magnetic environment would always generate a voltage. In Faraday’s law, it is clear that there are different ways on how to generate a voltage.