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kkurt [141]
2 years ago
6

How many atoms are in a sample of chromium with a mass of 31 grams? O a 2.4 x 1024 atoms of chromium b 3.6 x 1023 atoms of chrom

ium 1.9 x 1026 atoms of chromium Od 1.5 x 1023 atoms of Chromium​
Chemistry
1 answer:
lukranit [14]2 years ago
4 0

Answer:

b. 3.66x10²³ atoms of chromium.

Explanation:

First we calculate how many moles are there in 31 grams of chromium, using its molar mass:

  • Molar Mass of Chromium = 51 g/mol (This can be found on any periodic table)
  • 31 g ÷ 51 g/mol =  0.608 mol

Then we <u>calculate how many atoms are there in 0.608 moles</u>, using <em>Avogadro's number</em>:

  • 0.608 mol * 6.023x10²³ atoms/mol = 3.66x10²³ atoms

The correct answer is thus option b. 3.66x10²³ atoms of chromium.

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Elemental sulfur is one of the products of the gas-phase reaction of nitric acid and hydrogen sulfide. The other
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Answer:

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8 0
2 years ago
(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak
Taya2010 [7]

Answer:

Here's what I get  

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

                   H₂ +    I₂    ⇌ 2HI

I/mol·L⁻¹:    0.30   0.15         x

2. Calculate the concentration of HI

Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} =  5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

 

7 0
3 years ago
Which statement best describes a physical change?
Pepsi [2]

Answer:

The answer is c

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3 years ago
PLEASE HElP ASAP!!!!!!
stepan [7]

Answer:

1 hour

Explanation:

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When balance the following chemical equations N2+O2= NO2 the coefficient for O2 is
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Answer:

2

Explanation:

N₂ + O₂ --->  NO₂

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N₂ + 2O₂ ---> 2NO₂

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2 years ago
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