Hello!
In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.
We have the following data:
m(Fe) - mass of iron = 28 g
m(S) - mass of sufur = 16 g
MM(Fe) - molar mass of iron ≈ 56 g/mol
MM(S) - molar mass of sulfur ≈ 32 g/mol
n(Fe) - number of mol of iron = ?
n(S) - number of mol of sulfur = ?
Solving:
* to n(Fe)
![n_{Fe} = \dfrac{m_{Fe}}{MM_{Fe}}](https://tex.z-dn.net/?f=n_%7BFe%7D%20%3D%20%5Cdfrac%7Bm_%7BFe%7D%7D%7BMM_%7BFe%7D%7D)
![n_{Fe} = \dfrac{28\:\diagup\!\!\!\!\!g}{56\:\diagup\!\!\!\!\!g/mol}](https://tex.z-dn.net/?f=n_%7BFe%7D%20%3D%20%5Cdfrac%7B28%5C%3A%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21g%7D%7B56%5C%3A%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21g%2Fmol%7D)
![\boxed{n_{Fe} = 0.5\:mol}](https://tex.z-dn.net/?f=%5Cboxed%7Bn_%7BFe%7D%20%3D%200.5%5C%3Amol%7D)
* to n(S)
![n_{S} = \dfrac{m_{S}}{MM_{S}}](https://tex.z-dn.net/?f=n_%7BS%7D%20%3D%20%5Cdfrac%7Bm_%7BS%7D%7D%7BMM_%7BS%7D%7D)
![n_{S} = \dfrac{16\:\diagup\!\!\!\!\!g}{32\:\diagup\!\!\!\!\!g/mol}](https://tex.z-dn.net/?f=n_%7BS%7D%20%3D%20%5Cdfrac%7B16%5C%3A%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21g%7D%7B32%5C%3A%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21g%2Fmol%7D)
![\boxed{n_{S} = 0.5\:mol}](https://tex.z-dn.net/?f=%5Cboxed%7Bn_%7BS%7D%20%3D%200.5%5C%3Amol%7D)
The stoichiometric reaction will be in the same proportion (1 : 1), let us see:
![Fe + S \Longrightarrow FeS](https://tex.z-dn.net/?f=Fe%20%2B%20S%20%5CLongrightarrow%20FeS)
1 mol of Fe -------------- 1 mol of FeS
0.5 mol of Fe ------------ 0.5 mol of FeS
Will the reaction of the iron mass with the mass of sulfur produce how many grams of iron sulfide? We will see:
n(FeS) - number of mol of iron sulfide = 0.5 mol
m(FeS) - mass of iron sulfide = ? (in grams)
MM(FeS) - Molar Mass of iron sulfide = 56 + 32 = 88 g/mol
Solving:
![n_{FeS} = \dfrac{m_{FeS}}{MM_{FeS}}](https://tex.z-dn.net/?f=n_%7BFeS%7D%20%3D%20%5Cdfrac%7Bm_%7BFeS%7D%7D%7BMM_%7BFeS%7D%7D)
![m_{FeS} = n_{FeS}*MM_{FeS}](https://tex.z-dn.net/?f=m_%7BFeS%7D%20%3D%20n_%7BFeS%7D%2AMM_%7BFeS%7D)
![m_{FeS} = 0.5\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}*88\:\dfrac{g}{mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}](https://tex.z-dn.net/?f=m_%7BFeS%7D%20%3D%200.5%5C%3Amol%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5Cdfrac%7B%5Chspace%7B0.6cm%7D%7D%7B~%7D%2A88%5C%3A%5Cdfrac%7Bg%7D%7Bmol%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5Cdfrac%7B%5Chspace%7B0.6cm%7D%7D%7B~%7D%7D)
![\boxed{\boxed{m_{FeS} = 44\:g}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7Bm_%7BFeS%7D%20%3D%2044%5C%3Ag%7D%7D%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5Cbf%5Cblue%7B%5Ccheckmark%7D%5Cbf%5Cgreen%7B%5Ccheckmark%7D%5Cbf%5Cred%7B%5Ccheckmark%7D)
Answer:
44 grams of iron sulfide
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