p = mv so this question pertains to conservation of momentum.
The momentum of the car is 1320*12 = 15840kgms^-1
For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.
So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m
Rearranging to solve for m
7.9m = 17820
m = 2255.70 = 2300kg to 2sf
Answer:0.0242 Nm
Explanation: The distance of 0.145 mm is very small. This will also result in a small ttorque. The question would make more sense if the distance was 0.145 m. Answering with the 0.145 mm as distance :
Changin from mm to m : 1mm=0.001m
0.145 mm = 0.000145 m
The formula for Torque is T=Fxd
Wher F is the force and d is the perpendicular distance between the centre of the bolt and the applied force.
T= 167 x 0.000145 = 0.024215 Nm
Electrical charges on one or more particles within the field cause the electric field
Each point in space has an electric field associated with it when a charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field
A region of space surrounding an electrically charged particle or object known as an electric field is one in which an electric charge would experience force. A vector quantity called an electric field can be represented by arrows pointing in the direction of or away from charges. The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
To learn more about electric field please visit - brainly.com/question/15800304
#SPJ1
Answer: The volume is: " 1.430 cm³ " .
_____________________________
Explanation:
________________________
Volume, " V = ? ; (unknown, we need to solve for this).
Density, "D = 19.32 g / cm³ ;
mass , "m" = 27.63 g ;
_____________________________________________
The formula for density is:
____________________________________________
D = m / V ; Divide each side of the equation by: "(1/m)" ;
to isolate " V" on one side of the equation; and to solve for "V" ;
____________________________________________
1/m)*D = (1/m) * (m / V) ;
_______________________________
to get:
_______________________________
D/m = ; ↔ 1 / V ; Take the reciprocal of EACH SIDE; to isolate "V" on each side of the equation:
_____________________________
m / D = V/1 ↔ V = m / D ;
_____________________________
V = m / D ;
_______________________________
Now, plug in our given values for mass, "m" ; and Density, D"; to solve for "Volume, V " ;
_____________________________________
V = m / D = (27.63 g) ÷ (<span>19.32 g / cm</span>³) ;
= (27.63 g) * (1 cm³ / 19.32 g) ;
= (27.63 ÷ 19.32) cm³ ;
= 1.4301242236024845 cm³ ;
→ Round to "4 significant figures" ;
= 1.430 cm³ .
____________________________________________
The volume is: " 1.430 cm³ " .
______________________________________________
A) Starting from rest, we have the entire cycle determined by 0.8s.
If we assume a constant movement, half of that time is when it reaches the highest point, that is, in 0.4s.
The distance as a function of speed and acceleration is given by,
At the initial point the speed is zero and the acceleration is equivalent to gravity.
B) When returning to the ground, the final speed is zero. Therefore, the equation that relates velocity to acceleration is given by,
