A car accelerates at 3 m/s*2. Assuming the car starts from rest, how much time does it need to
2 answers:
We are given with some parameters used in Kinematics for determining the motion of an object.
- Accleration = 3 m/s²
- Started from rest (Initial vel.) = 0 m/s
- Final velocity = 12 m/s
We have to find the time taken by the car to attain the final velocity with the given accleration. By using 1st equation of motion which says:
- v = u + at
Final velocity = Initial velocity + Accl. × Time taken
Plugging the values,
➝ 12 = 0 + 3(t)
➝ 3t = 12
➝ t = 4 s
So, the correct answer is Option C. And we are done...
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Answer:
The product of the decay its Sulfur-32
Explanation:
Phosphorus-32 ( lets write it , where the number above its the atomic mass and the number below the atomic number) decays turning a neutron into a proton and emitting radiation on the form of a electron. This is the beta minus decay, and, actually, an electronic antineutrino its also produced. We can write this decay for an X isotope with a Y isotope produced as:
where its the electron, and
the electronic antineutrino . We can see that the atomic number increases by one (cause a proton it produced and retained into the nucleus), and the atomic mass is approximately the same (there is a small difference between the neutron and proton mass, but its very small).
So, Phosphorus-32 (atomic number 15) will turn to an element with atomic number 16, and atomic mass 32, as:
.
.
The Y isotope must have an atomic number of 16 and an atomic mass of 32. The element with atomic number 16 its Sulfur (S), so, our decay its
.
and the product of such decay its Sulfur-32
if currents go in opposite directions, wires repel