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horsena [70]
4 years ago
10

A car accelerates at 3 m/s*2. Assuming the car starts from rest, how much time does it need to

Physics
2 answers:
Eduardwww [97]4 years ago
6 0

We are given with some parameters used in Kinematics for determining the motion of an object.

  • Accleration = 3 m/s²
  • Started from rest (Initial vel.) = 0 m/s
  • Final velocity = 12 m/s

We have to find the time taken by the car to attain the final velocity with the given accleration. By using 1st equation of motion which says:

  • v = u + at

Final velocity = Initial velocity + Accl. × Time taken

Plugging the values,

➝ 12 = 0 + 3(t)

➝ 3t = 12

➝ t = 4 s

So, the correct answer is Option C. And we are done...

Carry On Learning !

uranmaximum [27]4 years ago
5 0
<h3><u>Given</u><u>:</u><u>-</u></h3>

Acceleration,a = 3 m/s²

Initial velocity,u = 0 m/s

Final velocity,v = 12 m/s

<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>

Calculate the time take by a car.

<h3><u>Solution:-</u><u> </u></h3>

According to the first equation of motion:

v = u + at

★ Substituting the values in the above formula,we get:

⇒ 12 = 0 + 3 × t

⇒ 12 = 3t

⇒ 3t = 12

⇒ t = 12/3

⇒ t = 4 sec

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oksian1 [2.3K]

Answer:

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Explanation:

Given;

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duration of motion of the blade, t = 0.4 s

radius of the circle moved by the blade, r = 0.45 m

The angular speed of the blade in radian is calculated as;

\omega  = \frac{\theta}{t} \times \frac{\pi \ radian}{180^0} \\\\\omega  =  \frac{90.08 ^0}{0.4 \ s} \times \frac{\pi \ radian}{180^0} \\\\\omega  = 3.93 \ rad/s

The centripetal acceleration is calculated as;

a = ω²r

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3 years ago
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Answer:

Explanation:

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marishachu [46]

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4 years ago
A physical representation of a real object, such as a globe of the world, is an ___ model
densk [106]

Answer;

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A physical representation of a real object, such as a globe of the world, is a physical model.

Explanation;

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3 years ago
A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases
Mila [183]

Answer:

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Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

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Change in Pressure in the tank, \Delta P = 7.28\ mmHg

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Now,

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We know that:

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Also,

\Delta P = \rho_{o} gh

where

g = acceleration due to gravity

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970.656 = 900\times 9.8\times h

h = 0.11 m

Now, if mercury is used:

\Delta P = \rho_{m} gh

970.656 = 13600\times 9.8\times h

h = 0.00728 m = 7.28 mm

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