Question

Two similar parallelograms have areas of 18in^2 and 32in^2. find the ratio of their perimeters

Answer 1

   
$\displaystyle\\ k = \frac{P_1}{P_2} = \sqrt{ \frac{A_1}{A_2} }=\sqrt{\frac{18}{32}}=\sqrt{\frac{9\times2}{16\times2}}=\sqrt{\frac{9}{16}}=\frac{\sqrt{9}}{\sqrt{16}}= \boxed{\bf \frac{3}{4}}$