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Brilliant_brown [7]
3 years ago
5

What is the specific heat capacity of silver metal if 110.00 g of the metal

Chemistry
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

"0.24 J/g.k" is the appropriate solution.

Explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C  

Now,

The specific heat will be:

⇒  q=ms \Delta T

On putting the given values, we get

⇒  396=110.00\times s\times 15.0

⇒  396=s\times 1650

⇒      s=\frac{396}{1650}

⇒         =0.24 \ J/g.k

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Explanation:

Given data:

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Pressure = 765 torr ( 765/760 = 1.0 atm

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"What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0"
Artyom0805 [142]

Q: What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0 °C? (Lf = 3.34 x 105 J/kg)

Answer:

-3670.33 J/K

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Where ΔS = Change of entropy, ΔH = heat change, T = temperature.

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ΔH = - 1002000 J.

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4 0
3 years ago
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umka21 [38]

The reaction is<span>
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To balance the equation, both side have same number of elements. Here,</span>

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First, we have to balance number of C atoms and number of H atoms in both side.  
To balance C atoms, '2' should be added before CO</span>₂ and to balance H atoms, '2' should be added before H₂<span>O. 
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After balancing the equation should be,</span>

C₂H₄<span> + 3O</span>₂<span> → 2CO</span>₂<span> + 2H</span>₂O


8 0
3 years ago
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