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MariettaO [177]
3 years ago
5

If two animals can reproduce and produce fertile offspring, then they are members of the same ________________.

Chemistry
2 answers:
lina2011 [118]3 years ago
6 0

Answer: Species

Explanation:

If two animals can reproduce and  the offspring that is produced is also fertile then it can be said that they are members of the same species.

The population of the same species live together in search of food, mate with each other to produce offspring, compete for food and compete for other resources.

It does not matters that the organism live in the same place or different, if they mate and produce a fertile offspring they belong to the same species.

ikadub [295]3 years ago
5 0

Answer:

The answer is C. Species

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Answer:

m_{H_2SO_4}=81.7gH_2SO_4

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Based on the given undergoing chemical reaction is is rewritten below:

2Al (s) + 3H_2SO_4 (aq)\rightarrow  Al _2(SO4)_3 (aq) + 3H_2 (g)

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2

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An unknown compound contains 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by mass. A mass spectrometry analysis reveals that
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Answer:

Molecular formula is C₂₆H₃₆O₄

Explanation:

The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.

In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H

In 412 g of compound we would have:

(412 . 75.69) / 100 = 311.8 of C

(412 . 15.51) / 100 = 63.9 g of O

(412 . 8.80) / 100 = 36.2 g of H

Now, we can determine the moles of each, that are contained in 1 mol of compound.

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36 g / 1 g/mol = 36 H

Molecular formula is C₂₆H₃₆O₄

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