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3 years ago

A sample has a mass of 15 g and a volume of 3 mL calculate the density

Chemistry

1 answer:

zlopas [31]3 years ago

7 0

Since density is mass/volume, the density is 5g/ml.

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When sodium peroxide is added to water, sodium hydroxide and oxygen gas is produced.

lukranit [14]

Answer:

The reaction combines the sodium with the hydrogen and oxygen in water to form sodium hydroxide and hydrogen gas, and you get a lot of energy released as heat as well. This heat actually melts any remaining sodium that has not reacted yet, and ignites the hydrogen gas, so you get the bang and the flash.

Explanation:

8 0

2 years ago

At a certain concentration of H2 and NH3, the initial rate of reaction is 0.120 M / s. What would the initial rate of the reacti

mel-nik [20]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

$rate=k[H_2]^2[NH_3]$

At a certain concentration of $H_2 and [tex]I_2, the initial rate of reaction is 0.120 M/s. What would the initial rate of the reaction be if the concentration of [tex]H_2 were halved.Answer : The initial rate of the reaction will be, 0.03 M/sExplanation :Rate law expression for the reaction:[tex]rate=k[H_2]^2[NH_3]$

As we are given that:

Initial rate = 0.120 M/s

Expression for rate law for first observation:

$0.120=k[H_2]^2[NH_3]$ ....(1)

Expression for rate law for second observation:

$R=k(\frac{[H_2]}{2})^2[NH_3]$ ....(2)

Dividing 2 by 1, we get:

$\frac{R}{0.120}=\frac{k(\frac{[H_2]}{2})^2[NH_3]}{k[H_2]^2[NH_3]}$

$\frac{R}{0.120}=\frac{1}{4}$

$R=0.03M/s$

Therefore, the initial rate of the reaction will be, 0.03 M/s

5 0

3 years ago

Based on the results of this lab, write a short paragraph that summarizes how to distinguish physical changes from chemical chan

qwelly [4]

Answer:

what were the results

Explanation:

3 0

3 years ago

Read 3 more answers

What is a physical property of milk

babymother [125]

Liquid, or aqueous (?)

7 0

3 years ago

A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa)?

AleksAgata [21]

<h3><u>Answer;</u></h3>

= 3032.15 kPa

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

= (5 × 0.08206 × 547)/7.5 L

= 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

<u>= 3032.15 kPa</u>

3 0

3 years ago