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PolarNik [594]
3 years ago
9

Someone please help me

Chemistry
1 answer:
Olegator [25]3 years ago
4 0

Answer:

Newton's first law.

Explanation:

It is the same as law of inertia.

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What pressure (in kilopascals) is exerted by 4.20 moles of Xenon gas in a 15.0 L container at 280.0 K?
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Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa

Explanation:

The question requires us to calculate the pressure, in kPa, connsidering the following information:

<em>number of moles = n = 4.20mol</em>

<em>volume of gas = V = 15.0L</em>

<em>temperature of gas = T = 280.0 K</em>

We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:

PV=nRT\rightarrow P=\frac{nRT}{V}

Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:

<em>R = 8314.46 L.Pa/K.mol</em>

Applying the values given by the question to the rearranged equation above, we'll have:

\begin{gathered} P=\frac{nRT}{V} \\  \\ P=\frac{(4.20mol)\times(8314.46L.Pa/K.mol)\times(280.0K)}{(15.0L)}=652\times10^3Pa \end{gathered}

Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.

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