Why is the earths Axis titled

1 answer:

7 0

Since obliquity is the angle between the axis of rotation and the direction perpendicular to the orbital plane, it changes as the orbital plane changes due to the influence of other planets. But the axis of rotation can also move (axial precession), due to torque exerted by the sun on a planet's equatorial bulge.
(Got it from google )

You might be interested in

Igneous rock___to form magma a)melts b)weathers c)compacts d)crystallizes NEED HELP ASAP

dangina [55]

Answer:

should be A)Melts.Because magma is liquid i think

5 0

2 years ago

Read 2 more answers

Which of the following determines the type of element that an atom makes?

emmainna [20.7K]

The answer is B, the number of protons

It's is the unique thing about every element!

3 0

2 years ago

Read 2 more answers

A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál

Svetllana [295]

Answer:

$\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%$

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

$m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g$

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

$m_T=180g+120g+135g+2.77g=437.77g$

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

$\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%$

¡Saludos!

5 0

2 years ago

For an entire species to survive, it must allow for new generations to maintain the population. This is the challenge of _______

a_sh-v [17]

I think it’s gathering food or maintaining structure.

4 0

1 year ago

What is the ph of a solution containing 0.12mol/l of nh4cl and 0.03 mol/l of naoh (pka is 9.25)?

Alborosie

Given the following:

Concentration of residual (NH4)+ = 0.12 - 0.03 = 0.09 mol / L
Concentration of created NH3 = 0.03 mol / L

The (NH4) + reacts with all (OH)- to form NH3 and H2O ( Water )

The resultant solution is NH4+ / NH3 buffer system in which (NH4)+ is acid and the NH3 is base or as called the salt.

For a buffer system :

pH = pKa + Log (acid) / (salt)
  = 9.25 + Log [ (NH4)+ ] / [ NH3 ]
   = 9.25 + Log [ 0.09 ] / [ 0.03 ]
   = 9.25 + Log 3
   = 9.25 + 0.4771
pH = 9.7271 or 9.73 which is rounded up to 2 decimal places

6 0

2 years ago

Read 2 more answers