The reaction is:
<span>4Li(s) + O2 (g) = 2Li+ + 2O-2(s).
The oxidizing agent is the one that is being reduced which is oxygen where the charge changed from neutral to -2 while the reducing agent is the on being oxidized which is lithium where the charge change from neutral to +1.</span>
A Hydrogen bond will stablish between the protons of the water and the free electron pairs of the electronegative atoms on asparagine, so:
a) can make up to 2 hydrogen bonds, since it has 2 free electron pairs.
b) can make up to 3 hydrogen bonds, since the negative charge makes up for 1 free electron pair aditional to the 2 oxygen already has.
c) can make up to 1 hydrogen bond, since it has 1 free electron pair.
d) since they have no free electron pairs, they cannot establish hydrogen bonds.
Answer:
C6 H12 O6 + 6 O2 → 6 C O2 + 6 H2 O + energy
Explanation:
1.
The balanced chemical reaction is:
N2 +3 I2 = 2NI3
We are given the amount of product formed.
This will be the starting point of our calculations.
3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3
mol I2 / 2 mol NI3 ) = 0.014 mol I2.
Thus, 0.014 mol of I2 is needed to form the
given amount of NI3.
