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3 years ago

PLS HELP!!

Chemistry

1 answer:

Gnesinka [82]3 years ago

3 0

Answer:

from the 1st equation:

4NH3 4NO

4 *(68) 4*30

1216 X mass of NO = 536.5 g

from the 2nd Equation

2NO 2NO2

2*30 2* 46

536.5 x mass of NO2 = 822.6 grams

from the 3rd Equation

3NO2 2HNO3

3*(46) 2* (63)

822.6 X mass of nitric acid = 751.06 gram

b) % yields = ( 96.2%* 91.3% *91.4%)= 80.3%

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In 44g of carbon dioxide, 12 g of carbon is contained.

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In 18g of water, 2 g of hydrogen is contained.

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Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.000286g}{1g/mole}=2.86\times 10^{-4}moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.000774g}{16g/mole}=4.83\times 10^{-5}moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is $4.83\times 10^{-5}mol$

For Carbon = $\frac{1.43\times 10^{-4}}{4.83\times 10^{-5}}=2.96\approx 3$

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