Answer:
0.8162 gramos de plomo por gramo de yodo
1.633 gramos de plomo por gramo de yodo
Explanation:
Asumiendo una base de 100 gramos para cada compuesto:
Primer compuesto:
Gramos plomo: 44.94g
Gramos de yodo: 100-44.94g = 55.06g
Así, la masa de plomo por gramos de yodo para el primer compuesto es:
44.94g plomo / 55.06g Yodo =
<em>0.8162 gramos de plomo por gramo de yodo</em>
<em></em>
Segundo compuesto:
Gramos plomo: 62.02g
Gramos de yodo: 100-62.02g = 37.98g
La masa de plomo por gramos de yodo para el segundo compuesto es:
62.02g plomo / 37.98g Yodo =
<em>1.633 gramos de plomo por gramo de yodo</em>
Answer:
The Kₐ of the weak acid is 1.033×10⁻⁴
Explanation:
The dissociation of a weak acid in aqueous solution is limited to about 5 to 10%
The acid dissociation reaction is given as follows;
HA (aq) + H₂O (l) → H₃O⁺(aq) + A⁻ (aq)
Given that the pH = 2.5, we have
pH = -log₁₀[H₃O⁺] = 2.5
∴ [H₃O⁺] = 10^(-2.5) = 0.0031623
![K_a = \dfrac{[H_3O^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5BH_3O%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
Kₐ = [H₃O⁺][A⁻]/[HA] = (0.0031623^2)/(0.1 - 0.0031623) = 1.033×10⁻⁴
The acid dissociation constant, Kₐ for weak acid is very low as obtained
Well, when 1-propanol is heated in the presence of an acid produces Cyclopropane and water. one example of this is when we heat propanol (CH3CH2CH2OH) with an acid like HCl. if we do the balancing like this: CH3CH2CH2OH + HCl -> CH3CH2CH2Cl + H2O we obtain the Cyclopropane and water.
Molecules are made up of atoms that are held together by chemical bonds.
Density=mass/volume
0.7198=m/11.84
mass=0.06g
