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Helga [31]
3 years ago
15

Problem Page Suppose 25.1g of barium nitrate is dissolved in 200.mL of a 0.50 M aqueous solution of ammonium sulfate. Calculate

the final molarity of nitrate anion in the solution. You can assume the volume of the solution doesn't change when the barium nitrate is dissolved in it. Round your answer to 3 significant digits.
Chemistry
1 answer:
melomori [17]3 years ago
3 0

Answer:

1.26 M

Explanation:

The ion nitrate is NO₃⁻ and the Barium is from group 2 so it forms the ion Ba²⁺, so the barium nitrate has the formula: Ba(NO₃)₂. The molar masses are: Ba: 137 g/mol, N = 14 g/mol, O = 16 g/mol, so the molar mass of barium nitrate is:

137 + 2x(14 + 3x16) = 199 g/mol

The number of moles is the mass divided by the molar mass, so:

n = 25.1/199 = 0.126 mol of Ba(NO₃)₂

In 1 mol of the salt, there are 2 moles of NO₃⁻, so the number of moles of nitrate is 0.252 mol. Nitrates formed with ammonium (that can react when the solid dissolves) and with elements from group 1 and 2 are completely soluble in water. So, the moles of nitrate will remain 0.252 mol.

The molarity is the number of moles divided by the volume (0.2 L):

[NO₃⁻]= 0.252/0.2 = 1.26 M

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Answer:

Options d.

Explanation:

As white light from the sun is passed through a prism, it is separated into colors - red, violet, yellow, blue, green, orange, and indigo.

Dispersion is the process of the separation of visible light into its different component colors. The light waves are refracted as they enter the prism.

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4 0
3 years ago
_Al(NO3)3 +_(NH4)3 P04_AlPO4+_ NH, NO3<br>balancing equations​
astra-53 [7]

Answer:

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Explanation:

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The above equation can be balance as illustrated below:

Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + NH₄NO₃

There are 12 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 3 before NH₄NO₃ as shown below:

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Now the equation is balanced.

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4 0
2 years ago
A sample of lead has a density of 11.3 g/cm3 and a mass of 123 grams, what is the volume of the sample?
SVEN [57.7K]

Answer:

The answer is

<h2>11.18 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 123 g

density = 11.3 g/cm³

The volume is

volume =  \frac{123}{11.3}   \\  = 11.18181818...

We have the final answer as

<h3>11.18 cm³</h3>

Hope this helps you

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