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wariber [46]
3 years ago
10

What is the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml?

Chemistry
1 answer:
Firdavs [7]3 years ago
6 0

Answer: The final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock CuSO_4 solution = 2.5 M

V_1 = volume of stock CuSO_4solution = 5 ml  

M_1 = molarity of diluted CuSO_4 solution = ?

V_1 = volume of diluted CuSO_4 solution = 750 ml

Putting in the values we get:

2.5\times 5=M_2\times 750

M_2=0.017

Therefore the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

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Explanation:

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8 0
3 years ago
There are 1.204 x 10^24 atoms of oxygen. How many moles is this?
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7.25 x 10^47

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7 0
3 years ago
When mixed, solutions of silver nitrate, AgNO3, and sodium sulfate, Na2SO4, form a precipitate of silver sulfate, Ag2SO4. The ba
Maslowich

Answer:

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

Explanation:

The general schemefor a reaction is given as;

Reactants --> Products

In this question, the reactants are AgNO3 and Na2SO4. The product is Ag2SO4.

The equation is given as;

AgNO3 + Na2SO4 --> Ag2SO4

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The full reaction is given as;

AgNO3 + Na2SO4 --> Ag2SO4 + NaNO3

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The balanced equation is given as;

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3 0
3 years ago
Which of these equations is balanced?
mel-nik [20]
A and b are balanced
4 0
3 years ago
Read 2 more answers
Consider the reaction.
Alex_Xolod [135]

Note the signs of equilibrium:-

  • Reaction don't procede forward or backward
  • Concentration of products and reactants remains same .

So

if

Concentration of A is 2M then concentration of B should be same .

So equilibrium constant K is 1

\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}

So

  • [B]=[A]^2
  • [B]=2^2
  • [B]=4M
8 0
2 years ago
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