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cluponka [151]
3 years ago
7

A 3.00 kg pool ball is moving to the left with a speed of 4.30 m/s without friction. If it experiences an impulse of -4.00 Ns, w

hat is the object's speed and direction after the impulse occurs?
Physics
1 answer:
brilliants [131]3 years ago
3 0

Explanation:

Given that,

Mass of thee pool ball, m = 3 kg

Initial speed of the ball, u = -4.3 m/s

Impulse experienced by thee ball, J = -4 N-s

To find,

Speed of the object after impulse occurs and its direction.

Solution,

Let left side is negative and right side is positive. So, the change in momentum or the impulse is given by the following expression as :

J=m(v-u)

v=\dfrac{J}{m}+u

v=\dfrac{-4}{3}+(-4.33)

v = -5.663 m/s

So, the speed of the object is 5.663 m/s and it is towards left.

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Answer:

v= 4.0 m/s

Explanation:

  • When standing on the bathroom scale within the moving elevator, there are two forces acting on Henry's mass: Normal force and gravity.
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  • As the gravity is larger than normal force, this means that the acceleration is downward, so, we choose this direction as the positive.
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  • We can find the speed after the first 3.8 s (assuming a is constant), applying the definition of acceleration as the rate of change of velocity:

        v_{f} = a* t = 1.05 m/s * 3.8 m/s = 4.0 m/s

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  • As the elevator  was moving, the only choice is that it is moving at  a constant speed, the same that it had when the scale was read for the first time, i.e., 4 m/s downward.
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