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nirvana33 [79]
2 years ago
11

Questions 1-5 please (:1.2.3.4.5.

Mathematics
1 answer:
Mumz [18]2 years ago
8 0
1. b
2. b
3. b
4. b
5. b
i am not sure about 1
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The tile along the edge of a triangular community pool needs to be replaced.
Gre4nikov [31]

Answer:

Third option: 12x^2+8x+25

Step-by-step explanation:

s1=8x^2

s2=4x^2+15

s3=8x+10

Total perimeter of the pool edge: P

P=s1+s2+s3

Replacing s1, s2 and s3 in the formula above:

P=(8x^2)+(4x^2+15)+(8x+10)

P=8x^2+4x^2+15+8x+10

Adding like terms:

P=12x^2+8x+25

6 0
3 years ago
Read 2 more answers
Idk the answer can u help me
valentinak56 [21]

The answer is C) 67

Angle FGE is a right angle so it is 90 degrees and angle AGF is the same as CGD so it is 23 degrees.

Add angle FGE and angle AGF together (90 + 23 = 113) and subtract that by 180 (180 - 113 = 67)

3 0
2 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
(8a^3÷27x^-3)1÷3 simplify<br>​
Damm [24]

Answer: (8a^3x^3)/81

Step-by-step explanation: Simplifying the expression :)

8 0
2 years ago
Read 2 more answers
Find the radius of a circle with a circumference of 96 feeer
Gnesinka [82]
The formula for circumference is C = 2πr.

The question gives you the circumference (C in the formula), and you need to find the radius (r in the formula). Begin by isolating r in the circumference formula.

C = 2πr
C/2π = r
r = C/2π

Now you can plug 96 for C and solve to find r.

r = C/2π
r = 96/2π
r ≈ 96/6.28
r ≈ 15.29

Answer:
The radius of a circle with a circumference of 96 feet is approximately 15.29 feet.
3 0
2 years ago
Read 2 more answers
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