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zlopas [31]
3 years ago
8

Jake can mulch a garden in 30 minutes. together, jake and ross can mulch the same garden in 16 minutes. how much time t, in minu

tes, will ti take ross to mulch the garden when working alone?
Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

"Jake can mulch a garden in 30 minutes." So, for 1 min Jake can mulch 1/30 part of a garden.

Ross can mulch the park for x minutes. So, for 1 min Jake can mulch 1/x part of a garden.

If they work together, for 1 min they will mulch (1/30 + 1/x) part of the garden.

At the same time, we know, that of they work together they can mulch the garden in 16 min, so for 1 min they will mulch 1/16 part of the garden.

Now, we can write an equation

\frac{1}{30}  + \frac{1}{x} = \frac{1}{16}  \\ \\ \frac{1}{x} = \frac{1}{16} - \frac{1}{30}  \\ \\ \frac{1}{x} =\frac{30-16}{16*30}  \\ \\ \frac{1}{x} =\frac{14}{16*30}  \\ \\x=\frac{16*30}{14}

x≈34.3 (min)

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Mai, Eric, and Dean served a total of 103 orders on Monday. Mai served 8 more orders than Eric. Dean served 3 times as many orde
mel-nik [20]
Let the number of orders Eric served be x

Eric = x
Mai =  x+ 8         [Mai served 8 more than Eric]
Dean = 3x           [Dean served 3 times as many as Eric]

Given that the total is 103
x + x + 8 + 3x = 103  
5x + 8 = 103
5x = 103 - 8
5x = 95
x = 19


x = 19
x + 8 = 19 + 8 = 27
3x = 19 x 3 = 57

Eric served 19
Mai served 27
Dean served 57





3 0
3 years ago
Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thiev
erik [133]

Answer: Probability that both the pirate and the Captain hit each other's ships is \frac{1}{9}

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

\frac{4}{9}

Probability that the pirate hits the Captains's ship is given by

\frac{1}{4}

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship"  is given by

P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}

Hence, probability that both the pirate and the Captain hit each other's ships is \frac{1}{9}

6 0
3 years ago
Given y < 4x – 6, explain how to graph this and decide whether or not (– 1, 5) is a solution to this inequality
svp [43]

the point (-1,5 ) is NOT a solution to the inequality.

There are three steps in graphing an inequality:

Rearrange the equation so "y" is on the left and everything else on the right.

Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

Shade above the line for a "greater than" (y> or y≥)

or below the line for a "less than" (y< or y≤).

Now to solve this, graph the line y=4x-6

Lets use the point (0,0)

0<-6, is NOT true

So we shade everything to the left of the line y=4x-6

Hope that helped.

4 0
3 years ago
One tossed coin landing heads and the next landing tails
bogdanovich [222]

Answer:

1/4 or 0.25

Step-by-step explanation:

*I'm assuming you're asking about the probability of this happening...

There are 4 different results you can get when flipping a coin twice...

First Flip: heads

Second Flip: tails

First Flip: heads

Second Flip: heads

First Flip: tails

Second Flip: heads

First Flip: tails

Second Flip: tails

only one of these is heads, then tails, so our probability is

1/4, or 0.25

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xxMikexx [17]

Answer:

29

Step-by-step explanation:

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6 0
2 years ago
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