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zlopas [31]
4 years ago
8

Jake can mulch a garden in 30 minutes. together, jake and ross can mulch the same garden in 16 minutes. how much time t, in minu

tes, will ti take ross to mulch the garden when working alone?
Mathematics
1 answer:
Gelneren [198K]4 years ago
8 0

"Jake can mulch a garden in 30 minutes." So, for 1 min Jake can mulch 1/30 part of a garden.

Ross can mulch the park for x minutes. So, for 1 min Jake can mulch 1/x part of a garden.

If they work together, for 1 min they will mulch (1/30 + 1/x) part of the garden.

At the same time, we know, that of they work together they can mulch the garden in 16 min, so for 1 min they will mulch 1/16 part of the garden.

Now, we can write an equation

\frac{1}{30}  + \frac{1}{x} = \frac{1}{16}  \\ \\ \frac{1}{x} = \frac{1}{16} - \frac{1}{30}  \\ \\ \frac{1}{x} =\frac{30-16}{16*30}  \\ \\ \frac{1}{x} =\frac{14}{16*30}  \\ \\x=\frac{16*30}{14}

x≈34.3 (min)

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5x-6=2x how do i get x
snow_lady [41]
You will need to do the following

You need to get both of the X's on the same side

So you will take the 5x and subtract it to the other side to get

-6=-3x 

-3 times 2 = -6 so therefore -6=-6

-6= -3(2)

Answer: X= 2

7 0
3 years ago
1. Using the formula for the probability of one event or another event, calculate the probability of drawing a card from a stand
ddd [48]
A standard deck has 52 cards.
A standard deck has 4 jacks.
A standard deck has 13 clubs.

From this, we can derive the following:
The probability of drawing a jack is 4/52 or 1/13
The probability of drawing a club is 13/52 or 1/4

But since the problem asks for drawing jack or club, therefore we should add the 2 probabilities, making 17/52. This is not the final answer yet. We know that there is a jack of clubs, therefore we need to subtract 1 from the probabilities since jack of clubs were considered in the 2 categories of probability.

With that being said, the probability of drawing a club or a jack is 16/52 or 4/13

Bonus Question:

The first thing you need to do here is find the probability of each scenario. First let's do what is given, the probability of drawing 2 aces. Since there are 4 aces in a deck of 52, we can easily say that the probability of drawing an ace is 4/52. However for our second draw, the probability of drawing a different ace is 3/51. This is so since we already drew a card that is an ace, hence we need to subtract one from the total aces (4-1) and from the total cards in the deck (52-1). In getting the probability of drawing two aces, we need to multiply the said probabilities: 4/52 and 3/51, resulting to 1/221.

For the second scenario, the drawing of 2 red cards, we just use the same concept but in this, we are already considering the 2 red cards in the first scenario, therefore the chance of drawing a red on our first draw is 24/52. For our second, we just need to subtract one card, therefore 23/51. Multiply these two and we will get 46/221.

Now, the problem asks for the chance of drawing either 2 reds or 2 aces, therefore we add the probabilities of the 2 scenarios:
46/222 + 1/221 = 47/221

Summary:
First Scenario:
4/52 + 3/51 = 1/221
Second Scenario:
24/52 + 23/51 = 46/221
Chances of drawing 2 red cards or 2 aces:
1/221 + 46/221 = 47/221
7 0
3 years ago
Equivalate a +4 when a=7
joja [24]

Answer:

11

Step-by-step explanation:

Plug in the variable into the equation. 7+4=11

6 0
3 years ago
Read 2 more answers
Need this answered quick
melisa1 [442]

95.7942857 pie form hope this is right got it off the internet so yeah



7 0
3 years ago
Question
mixas84 [53]
First you multiply 5*5 which is 25 and then you multiply 25*12 which is 300 and 300*14 is 4,200.so your answer is 4,200
7 0
3 years ago
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