Let the number of orders Eric served be x
Eric = x
Mai = x+ 8 [Mai served 8 more than Eric]
Dean = 3x [Dean served 3 times as many as Eric]
Given that the total is 103
x + x + 8 + 3x = 103
5x + 8 = 103
5x = 103 - 8
5x = 95
x = 19
x = 19
x + 8 = 19 + 8 = 27
3x = 19 x 3 = 57
Eric served 19
Mai served 27
Dean served 57
Answer: Probability that both the pirate and the Captain hit each other's ships is 
Step-by-step explanation:
since we have given that
Probability that the captain hits the pirate ship is given by

Probability that the pirate hits the Captains's ship is given by

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship" is given by

Hence, probability that both the pirate and the Captain hit each other's ships is 
the point (-1,5 ) is NOT a solution to the inequality.
There are three steps in graphing an inequality:
Rearrange the equation so "y" is on the left and everything else on the right.
Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
Now to solve this, graph the line y=4x-6
Lets use the point (0,0)
0<-6, is NOT true
So we shade everything to the left of the line y=4x-6
Hope that helped.
Answer:
1/4 or 0.25
Step-by-step explanation:
*I'm assuming you're asking about the probability of this happening...
There are 4 different results you can get when flipping a coin twice...
First Flip: heads
Second Flip: tails
First Flip: heads
Second Flip: heads
First Flip: tails
Second Flip: heads
First Flip: tails
Second Flip: tails
only one of these is heads, then tails, so our probability is
1/4, or 0.25
Answer:
29
Step-by-step explanation:
Would you mind giving me brainliest?