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vlabodo [156]
4 years ago
15

The specific heat(c) of copper is 0.39 J/g °C. What is the temperature

Physics
1 answer:
horsena [70]4 years ago
8 0

Answer:12.8°c

Explanation:

specific heat capacity of copper(c)=0.39J*g°c

Mass(m)=20grams

Quantity of heat(Q)=100joules

Temperature rise(@)=?

@=Q/(mxc)

@=100/(20x0.39)

@=100/7.8

@=12.8°c

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const2013 [10]

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

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4 years ago
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Answer:

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Explanation:

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4 years ago
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Nimfa-mama [501]

Answer:

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Explanation:

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\omega_0 = \sqrt{\frac{k}{m}}

here mass of the object is given as

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\omega_0 = \sqrt{\frac{220}{\frac{30}{9.81}}}

\omega_0 = 8.48 rad/s

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now we have

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3 years ago
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u is the coefficient of static friction

Making u subject of the formula we have that,

u = {450*(18²/106)} /4410

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NOTE: coefficient of friction is dimensionless. It as no Unit.

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