Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s
ees a flower pot go past his window ledge and Jill sees the same pot go past her window ledge a little while later. The time between the two observed events was 4.6 s. Assume air resistance is negligible. a) If the speed of the pot as it passes Jill's window is 58.0 m/s, what was its speed when Jack saw it go by?
b) What is the height between the two window ledges?
a) speed when Jack sees the pot : 12.92 meters per second
b) height difference 163.115 meters
Explanation:
First to calculate te initial speed we use the acceleration formula:
a= v1-v0/t
Acceleration being gravity's acceleration (9.8 m/s^2)
v1 being the speed when Jill sees the pot
v0 when Jack sees it
and t the time between
Solving for v0 it would be
v1 - a*t = v0
replacing
For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)
The angular momentum of an object is equal to the product of its moment of inertia and angular velocity. L = Iω I = 1/2 MR² I = 1/2 x 13 x (0.2) I = 1.3
Each pole would become tropical during summer, but be horribly cold during winter, far colder than they are now. But the equator would be in perpetual twilight during two seasons—and summer the opposing two.
