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malfutka [58]
3 years ago
9

How long will it take you to pass a truck at 60 mph with oncoming traffic?

Physics
2 answers:
DedPeter [7]3 years ago
6 0
<span>This is impossible to calculate without knowing the speed of each vehicle. </span>
kobusy [5.1K]3 years ago
5 0

Answer:

4 seconds - Not practical

Explanation:

Length of the truck = 50'

Initial distance behind the truck = 30'

Finish Pass = 50' ahead of truck ,

Pass at =  60mph -- about 3.375 seconds.

- 70mph your closing speed is 130mph.  

If you were less than a 1/4 mile away when you tried the pass you will be dead.

That would be a quick pass.  You will probably want a mile beyond the oncoming traffic.

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What angle is formed by the sun, the earth, and the moon during an eclipse?.
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3 years ago
Which of the following distinguishes electromagnetic waves from mechanical waves
Ivan

Answer:

Explanation:

1. Mechanical waves require material medium for their propagation while electromagnetic waves do not require material medium for their propagation.

2. Mechanical waves can either be transverse or longitudinal while electromagnetic waves are transverse.(Transverse waves are waves in which the vibration of the particules of the medium is perpendicular to the direction of the motion of wave. E.g water waves, waves of a plucked string and all electromagnetic waves RIVUXG . Longitudinal waves are waves whose vibration are parallel to the direction of the motion of the medium e.g waves in strings, sound waves.e.t.c)

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3 years ago
An astronaut throws a wrench in interstellar space. How much force is required to keep the wrench moving continuously with const
andreev551 [17]

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0 N

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3 years ago
A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this locati
sp2606 [1]

Answer:

a)T = 2.9*10^{-5} N-m

b) north edge will rise up

Explanation:

torque on the coil is given as

T = NIABsin\theta

where N is number of loop =  9 loops

i is current = 7.80 A

-B -earth magnetic field = 5.00*10^{-5} T

A- area of circular coil

A = \frac{\pi d^{2}}{4}

A =\frac{\pi .14^{2}}{4}

A =0.015 m2

PUTITNG ALL VALUE TO GET TORQUE

T = 9*7.8*0.015*5*10^{-5} sin{90-56}

T = 2.9*10^{-5} N-m

b) north edge will rise up

3 0
3 years ago
Read 2 more answers
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