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3 years ago

How long will it take you to pass a truck at 60 mph with oncoming traffic?

Physics

2 answers:

DedPeter [7]3 years ago

6 0

<span>This is impossible to calculate without knowing the speed of each vehicle. </span>

kobusy [5.1K]3 years ago

5 0

Answer:

4 seconds - Not practical

Explanation:

Length of the truck = 50'

Initial distance behind the truck = 30'

Finish Pass = 50' ahead of truck ,

Pass at = 60mph -- about 3.375 seconds.

- 70mph your closing speed is 130mph.

If you were less than a 1/4 mile away when you tried the pass you will be dead.

That would be a quick pass. You will probably want a mile beyond the oncoming traffic.

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A plumber is going to put two pipes in a wall, one in front and one in back. The pipes will be touching once they are installed.

beks73 [17]

Answer:

They become the same exact tempature

Explanation:

Since they got connected it should be the same.

8 0

3 years ago

(1.08×10-3)(9.3×10-4)

ira [324]

First you do the first parenthesis, (1.08 x 10 - 3) and you do it in the order of operations! (parenthesis, exponents, multiplication/division, add/subtract) to get 7.8. Then you take the second parenthesis (9.3 x 10 - 4) and do the same thing to get 89! You then times 7.8 by 89 to get 694.2! If it needs more elaboration just ask ^.^

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3 years ago

Two children are balanced on a seesaw that has a mass of 18.0 kg. The first child has a mass of 26.0 kg and sits 1.60 m from the

Mashcka [7]

Answer:

1.28 m

Explanation:

As shown in the diagram attached,

According to the principle of moment,

For a body at equilibrium,

Sum of clockwise moment = sum of anticlockwise moment.

Taking moment about the pivot,

W₁(1.6)+W(0.133) = W₂(x)............... Equation 1

Where W₁ = Weight of the first child, Wₓ = Weight of the seesaw, W₂ = weight of the second child, x = distance of the second child from the pivot.

But,

W = mg

Where g = 9.8 m/s², m = mass of the body

Therefore,

W₁ = 26×9.8 = 254.8 N,

Wₓ = 18×9.8 = 176.4 N

W₂ = 34.4×9.8 = 337.12 N

Substitute these values into equation 1

(254.8×1.6)+(176.4×0.133) = 337.12(x)

407.68+23.4612 = 337.12x

337.12x = 431.1412

x = 431.1412/337.12

x = 1.2789

x ≈ 1.28 m

7 0

3 years ago

Imagine a particle that has three times the mass of the electron. All other quantities given above remain the same. What is the

melamori03 [73]

Answer:

The only parameter that changes is mass m

It is only necessary to calculate the ratio Eh/Ee

$m_{h}=3m_{e}\\E_{h}=\frac{3m_{e}v^{2}}{2}\\E_{e}=\frac{m_{e}v^{2}}{2}\\\frac{E{h}}{E{e}}=3$

The kinetic energy of the heavy paricle is three times the kinetic energy of an electron

5 0

3 years ago

Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted

kkurt [141]

Answer:

E. The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

Explanation:

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7 0

3 years ago