Newton's second law states that (Force is mass times acceleration). Out of the given options, “a 10 kg ball thrown with a 50 Newton force”, an example have the greatest acceleration.
<u>Explanation:
</u>
To do the calculation, we already have the formula given derived from Newton’s second law of motion. To know the acceleration, we can simply modify the formula as,
For the 10kg ball threw in 50N, we have mass = 10 kg and Force = 50 N
Acceleration =
Similarly for 1 kg ball threw in 0.5N, substituting the values, we get
,
Acceleration =
For launching 50kg student by catapult of 100N,
acceleration =
For accelerating 500 kg car in 1000N engine,
acceleration =
Answer:
Gravity
Explanation:
Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all
Principles of conservation of linear momentum
Kinetic Energy before collision 60kJ
Kinetic Energy after collision 56.76kJ
Explanation:
1. Given data
mass m1= 1000kg
velocity u1= 10m/s
mass m2= 800kg
velocity u2= 5m/s
2. We want to find the common velocity after the collision
Applying the principle of conservation of linear momentum for inelastic collision we have
m1u1+m2u2= (m1+m2)V
substituting and solving for V
1000*10+800*5= (1000+800)V
10000+4000= 1800V
14000=1800V
3. Divide both sides by 1800
V= 14000/1800
V= 7.8m/s
4. Now let us find the kinetic energy of the two cars before the collision
For the first car
KE= 1/2m1u1^2
KE= 1/2*1000*10^2
KE=(1000*100)/2
KE= 100000/2
KE= 50000 Joules
KE= 50 kJ
For the second car
KE= 1/2m2u2^2
KE= 1/2*800*5^2
KE=(800*25)/2
KE= 20000/2
KE= 10000 Joules
KE= 10 kJ
Hence the total kinetic energy before the collision is
=50+10
=60kJ
After collision
KE= 1/2m1V^2
KE= 1/2*1000*7.8^2
KE=(1000*60.84)/2
KE= 60840/2
KE= 32420 Joules
KE= 32.42kJ
For the second car
KE= 1/2m2u^2
KE= 1/2*800*7.8^2
KE=(800*60.84)/2
KE= 48.672/2
KE= 24336 Joules
KE= 24.34 kJ
Hence the total Kinetic energy after collision is
=32.42+24.34
=56.76kJ
See the link below for more information on linear momemtum
https://brainly.in/question/17792506
Answer:
E = 1580594.95 N/C
Explanation:
To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:
(1)
dS: differential of the Gaussian surface
Qin: charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2
The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:
(2)
Qin is calculate by using the charge density:
(3)
Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.
The charge density is given by:
Next, you use the results of (3), (2) and (1):
Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:
hence, the electric field is 1580594.95 N/C
Answer:
The answer is B
Explanation:
The absorption happens when photons from light hit atoms and molecules, and they vibrate because of that specific interaction. Then the heat ejects from the object in the format of thermal energy.