Answer:
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The magnitude of the magnetic field inside the solenoid is
.
The given parameters;
- <em>length of the solenoid, L = 91 cm = 0.91 m</em>
- <em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
- <em>number of turns of the solenoid, N = 1300 </em>
- <em>current in the solenoid, I = 3.6 A</em>
The magnitude of the magnetic field inside the solenoid is calculated as;

where;
is the permeability of frees space = 4π x 10⁻⁷ T.m/A

Thus, the magnitude of the magnetic field inside the solenoid is
.
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The kinematic equations are used to <span>quantify motion in the case of uniform acceleration.
The other name is :
SUVAT equations, where the letters signify:
displacement (s),
initial velocity (u),
final velocity (v),
acceleration (a), and
time (t).
There are three equations are attached in the picture: </span>
Answer:
acceleration of the balloon is 11.4 m/s²
and
The instruments accelerate downwards at 9.8 m/s²
Explanation:
given data
mass = 5 kg
force = 106 N
acceleration of gravity = 9.8 m/s²
to find out
the acceleration of the balloon and the instruments
solution
we find weight of the instruments that is
weight W = mg
here m is mass and g is acceleration of gravity
W = 5 ×9.8
weight W = 49 N
and
so net upward force on the instruments is
net upward force F = 106 - 49
net upward force F = 57 N
and
The acceleration of the balloon is
Force = ma
57 = 5 a
a = 11.4 m/s²
acceleration of the balloon is 11.4 m/s²
and
The instruments accelerate downwards at 9.8 m/s²