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gavmur [86]
3 years ago
13

In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2

the mass has been lifted a distance D vertically upward. If we define the potential energy in Case 1 to be zero, what is the potential energy of Case 2
Physics
1 answer:
evablogger [386]3 years ago
4 0

Answer: hello your question is incomplete attached below is the complete question

answer :  1/2 KD^2  ( option A )

Explanation:

P.E ( potential energy ) = mgd

In case 1 P.E = 0   i.e. mgd = 0  

Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring

<u>The potential energy of the M in case 2 </u>

= P.E of M at rest + P.E of the spring

= 0 + 1/2 KD^2

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7 0
3 years ago
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The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medi
adoni [48]

Answer:

The value of new coulomb force is 1.43 N.

Explanation:

Given;

Coulomb's force in vacuum (air), F_v = 10 N

dielectric constant, K = 7

The Coulomb's force between two charges separated by a distance r in a vacuum is given as;

F_v = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2}

The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as

F_m = \frac{1}{4\pi K\epsilon_0} \frac{q_1q_2}{r^2}

Take the ratio of the two forces;

\frac{F_v}{F_m} = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2} \ \times \ \frac{4\pi K\epsilon_0 r^2}{q_1q_2} = K\\\\\frac{F_v}{F_m} = K\\\\\frac{10}{F_m} = 7\\\\F_m = \frac{10}{7} \\\\F_m = 1.43 \ N

Therefore, the value of new coulomb force is 1.43 N.

5 0
3 years ago
What should be the speed of an artificial satellite moving on a circular orbit around the Earth at a distance of 400 km from the
Drupady [299]

Answer:

7.67001846 km/s or 17157.38529 mph

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of the Earth =  5.972 × 10²⁴ kg

m = Mass of satellite

v = Velocity of satellite

The distance between the Earth's center and the satellite is

r = 6371000+400000 = 6771000 m

As the centripetal force balances the force of gravity we have

\frac{mv^2}{r}=\frac{GMm}{r^2}\\\Rightarrow v=\sqrt{\frac{GM}{r}}\\\Rightarrow v=\sqrt{\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{6771000}}\\\Rightarrow v=7670.01846\ m/s=7.67001846\ km/s

Converting to mph

7670.01846\times \frac{3600}{1609.34}=17157.38529\ mph

The velocity of the satellite is 7.67001846 km/s or 17157.38529 mph

5 0
3 years ago
In the semi arid regions of China, the country's inhabitants have practiced water harvesting for generations. Water harvesting i
lapo4ka [179]

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On the basis of the above description, By collecting run off during the rainy season for future irrigation increases the agricultural production is the correct option.

3 0
3 years ago
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A ball is launched directly in the air at a speed of 40 feet per second from a platform located 10 feet in the air. The motion o
crimeas [40]

Answer:

The ball will hit the ground in 2.73 s

Explanation:

Hi there!

f(t) is the height of the ball at time "t". We need to find the value of "t" for which f(t) = 0.

f(t) = 0   Then:

-16 · t² + 40 · t + 10 = 0  

Solving the quadratic equation using the quadratic formula (a = -16, b = 40, c = 10):

t = -0.23 s and t = 2.72 s

Since time can´t be negative, be discard that value.

The ball will hit the ground in 2.73 s.

Have a nice day!

8 0
3 years ago
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