In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2
1 answer:
Answer: hello your question is incomplete attached below is the complete question
answer : 1/2 KD^2 ( option A )
Explanation:
P.E ( potential energy ) = mgd
In case 1 P.E = 0 i.e. mgd = 0
Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring
<u>The potential energy of the M in case 2 </u>
= P.E of M at rest + P.E of the spring
= 0 + 1/2 KD^2
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Answer:
38.4 m/s
Explanation:
a) at t = 3.2s.
b) at t = 3.2 + Δt.
c) As Δt approaches 0. We can find the velocity by the ratio of Δx/Δt
As Δt approaches 0, v = 38.4 + 0 = 38.4 m/s