Answer:
2.218 m/s; 4.4375 m/s; 0.01981 m/s²
Explanation:
for more details see the attached picture.
In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2
1 answer:
Answer: hello your question is incomplete attached below is the complete question
answer : 1/2 KD^2 ( option A )
Explanation:
P.E ( potential energy ) = mgd
In case 1 P.E = 0 i.e. mgd = 0
Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring
<u>The potential energy of the M in case 2 </u>
= P.E of M at rest + P.E of the spring
= 0 + 1/2 KD^2
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<h2>F = kAρv²</h2>
Explained in the attachment !
<h3>Hope it helps you!!</h3>Answer:
The 3rd graph
Explanation:
A free body diagram is a diagram which shows all the forces acting on an object.
The problem asks us to find the free body diagram of block A, so we must find all the forces acting on block A.
We have 3 forces acting on block A in total:
- The force of gravity (its weight), which pushes the block downward (in the diagram, it is the force represented with
- The tension in the rope 1, which pulls block A upwards: this force is represented with
- The tension in the rope 2, due to the weight of block 2, which pulls block A downwards: this force is represented with
Based on the direction of these 3 forces, the correct diagram is the 3rd one.