Answer:
5.1*10^3 J/m^3
Explanation:
Using E = q/A*eo
And
q =75*10^-6 C
A = 0.25
eo = 8.85*10^-12
Energy density = 1/2*eo*(E^2) = 1/2*eo*(q/A*eo)^2 = [q^2] / [2*(A^2)*eo]
= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]
= 5.1*10^3 J/m^3
m = mass of the box
N = normal force on the box
f = kinetic frictional force on the box
a = acceleration of the box
μ = coefficient of kinetic friction
perpendicular to incline , force equation is given as
N = mg Cos30 eq-1
kinetic frictional force is given as
f = μ N
using eq-1
f = μ mg Cos30
parallel to incline , force equation is given as
mg Sin30 - f = ma
mg Sin30 - μ mg Cos30 = ma
"m" cancel out
a = g Sin30 - μ g Cos30
inserting the values
1.20 = (9.8) Sin30 - (9.8) Cos30 μ
μ = 0.44
The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.
<h3>What is current?</h3>
The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
For the given set of parallel resistors, we need to find the resistance of each resistor.
From the Ohm's law, V =IR
R = V/I
Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.
Thus, the student D gives enough evidence to find resistance of the circuit is
Learn more about current.
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Answer:
The length of open-open pipe needed is 6.23 m
The length of open-close pipe needed is 3.11 m
Explanation:
Fundamental frequency for standing wave mode of an open- open pipe is given by

where v is the velocity and L is the length
The length of open-open pipe needed is

Fundamental frequency for standing wave mode of an open- close pipe is given by

The length of open-close pipe needed is
