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Leya [2.2K]
2 years ago
8

Which two types of air masses would likely form a subtropical jet stream?

Physics
2 answers:
shepuryov [24]2 years ago
5 0
The exact location of the 'subtropical-jet stream' is located at the North phase of 30 Degrees and the reason behind this is due to the variation of air which lies on the region of mid-altitude and warmer equatorial air. the correct answer would be Cool and Warm air masses meeting near the equator.
kirill115 [55]2 years ago
3 0

Answer:

Cool and Warm air masses meeting near the equator.

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Two balls are kicked with the same initial speeds. Ball A was kicked at the angle 20° above horizontal and ball B was kicked at
GREYUIT [131]

Answer:

Ball A

Explanation:

Let the initial speed of the balls be u .

Angle of projection for ball A = 20°

Angle of projection for ball B = 75°

As we know that at highest point, the ball has only horizontal speed which always remains constant throughout the motion because the acceleration in horizontal direction is zero.

Speed of ball A at highest point = u Cos 20° = 0.94 u

Speed of ball B at highest point = u Cos 75° = 0.26 u

So, the ball A has bigger speed than B.

5 0
2 years ago
Saved
Anon25 [30]

Total distance moved by bead is 1.952 cm.

Explanation:

Let first consider all data that are given in question.

1.    F = 8 N                       ...force acting on string

2.   f  = 2 Hz                     ...frequency of system

3.   β = 4 cm = 0.04 m    ...wavelength of wave formed due to vibration           4.   A =  1 cm  = 0.01 m     ...Amplitude of vibration

Under certain conditions, waves can bounce back and forth through a particular region, effectively becoming stationary. These are called standing waves.

Here,it is due to vibration induced in spring due to tension induced in string

Standing wave equation is given by

y = (x,t) = 2A * sinK x * cos (wt)                ...(1)

Let first find, value of K, x, w, t

k = 2 * pi / beta                                          ....(2)

Where β is wavelength in meters

                   K is wave number

k = 2 * pi / 0.01

k = 628.31 m^{-1}

now, let us find value of w

W = 2 x pi x f                               ....(3)

                where f is frequency in hertz

W = 2 x pi x 2

W = 4 x pi

W = 0.08 \frac{m}{s}

y = (x,t) = 2A * sinK x * cos (wt)

now, let us find value of v that is wave speed

Notice that some x-positions of the resultant wave are always zero no matter what the phase relationship is.  These positions are called nodes.

Finding the positions where the sine function equals zero provides the positions of the nodes.

In our case, and      

K * x = pi

x = 0.04 / 2

x = 0.02

y = (0.02,1) = 2(0.01) * sin pi  * cos (12.5664 * 1)

y = (0.02,1) = 2(0.01) * -1  * cos 0.9761

Y = 1.952 cm

Finally, when bead is at middle of the string, total distance after stretch covered  is 1.952 cm.

3 0
3 years ago
Which of the following is the most reasonable weight in units of newtons for an average adult?
Oliga [24]

Answer: The reason weight for average adult is 530N

Explanation: The clearly see this answer, let's convert this weight to kg using F=mg

530=m×9.8

g is a constant of 9.8m/s2

We divide both sides by 9.8 to get

54kg then this weight is reasonable for an average adult.

7 0
3 years ago
Read 2 more answers
If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the
PolarNik [594]

Answer:

a. v₁ = 16.2 m/s

b. μ = 0.251

Explanation:

Given:

θ = 15 ° , r = 100 m , v₂ = 15.0 km / h

a.

To determine v₁ to take a 100 m radius curve banked at 15 °

tan θ  = v₁² / r * g

v₁ = √ r * g * tan θ

v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s

b.

To determine μ friction needed for a frightened

v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg

v₂ = 4.2 m/s

fk = μ * m * g

a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²

a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²

F₁ = m * a₁  ,  F₂ = m * a₂

fk = F₁ - F₂   ⇒  μ * m * g = m * ( a₁ - a₂)

μ * g = a₁ - a₂   ⇒  μ = a₁ - a₂ / g

μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)

μ = 0.251

3 0
3 years ago
How does the position of an object relate to the energy stored in an object?
Kamila [148]

Answer:

Potential Energy

Explanation:

Potential energy is the energy stored in an object due to it's position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.

4 0
2 years ago
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