The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Yes because you have the follow the order of operations.
Answer:
Its a
Step-by-step explanation:
Answer:
Step-by-step explanation:
The standard equation for a circle is given by:
Where (h, k) is the center and r is the radius.
We know that the center is (-4, 8). So, substitute -4 for h and 8 for k:
Simplify:
Now, we will need to find r.
We know that it passes through the point (-2, -1). So, we can substitute -2 for x and -1 for y and solve for r. So:
Evaluate:
Square:
Add:
So, r squared is 85.
We don’t actually have to solve for r itself, since we will have to square it anyways.
So, we have:
Substituting 85 for r squared, we get:
And we have our equation.
Answer:
385.7 ft
Step-by-step explanation:
The relation between speed, distance, and time is ...
distance = speed × time
<h3>Compatible units</h3>
The speed is given in miles per hour, but the time is given in seconds and the distance is wanted in feet. This suggests a conversion of speed to feet per second is appropriate.
<h3>Distance</h3>
The distance traveled is the product of this speed and the time period.