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ratelena [41]
3 years ago
14

Beet or cabbage juice can be used as:

Physics
2 answers:
Liula [17]3 years ago
5 0

bases is wrong I just took the test. im still not sure what the correct answer is but C. is wrong

STatiana [176]3 years ago
4 0
C bases. Have a great day :)
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As best you can, describe how we can tell the age of the Earth and rocks found on it.
Viktor [21]

Answer:

We can determine the age of the Earth and the rocks found on Earth with techniques such as measuring ice cores and digging and analysing fossils.

Explanation:

Hopefully this helped!

4 0
2 years ago
Carbon cycle diagram
sammy [17]

Carbon cycle shows is the continous movement of carbon in elemental and combined states on earth.

Steps :-

☆ Carbon moves from the atmosphere to plants. ...

☆ Carbon moves from plants to animals. ...

☆ Carbon moves from plants and animals to soils. ...

☆ Carbon moves from living things to the atmosphere. ...

☆ Carbon moves from fossil fuels to the atmosphere when fuels are burned. ...

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~ Benhemin360

6 0
2 years ago
Please help, thank you,
Elena-2011 [213]

same, stapler, gravity, motion, acceleration

6 0
3 years ago
A dock worker loading crates on a ship finds that a 27 kg crate, initially at rest on a horizontal surface, requires a 80 N hori
Aleksandr-060686 [28]

Answer:0.302

Explanation:

Given

mass of crate m=27 kg

Force required to set crate in motion is 80 N

Once the crate is set  in motion 56 N is require to move it with constant velocity

i.e. 80 N is the amount of force needed to just overcome static friction and 56 is the kinetic friction force

thus  

f_s(static\ friction)=\mu \cdot N

where \muis the coefficient of static friction and N is Normal reaction

N=mg

f_s=\mu mg

\mu mg=80

\mu =\frac{80}{27\times 9.8}

\mu =0.302

7 0
3 years ago
Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm

So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

7 0
3 years ago
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