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marishachu [46]

2 years ago

8

4.09 Lab: Sunrise, Sunset

1 answer:

Nimfa-mama [501]2 years ago

4 0

Latitude affects the length of the day due to the inclination of its axial tilt, which also influences the reception of sunlight.

<h3>What is Earth's inclination?</h3>

Earth's inclination makes reference to its axial tilt which is approximately 23.5 degrees.

Earth's inclination influence the amount of sunlight received by the Earth's surface, thereby affecting the length of the day at different latitudes.

This difference is more marked at high latitudes and near the Earth's poles, we have six months of plenty of light and six months of night.

In conclusion, latitude affects the length of the day due to the inclination of its axial tilt which also influences the reception of sunlight.

Learn more about the Earth's axial tilt here:

brainly.com/question/8678564

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Porque al tomar agua y la dejo en mi boca no se baja? Curiosidad xd

Varvara68 [4.7K]

Answer: eso no sabe. Xp

Explanation:

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What kind of weather would an occluded front likely bring?

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light of a certain frequency has a wavelength of 438 nm in water.What is the wavelength of this light in benzene

sveticcg [70]

Answer:

388.97 nm

Explanation:

The computation of the wavelength of this light in benzene is shown below:

As we know that

n (water) = 1.333

n (benzene) = 1.501

$\lambda (water) \times n(water) = \lambda (benzene) \times n(benzene)$

And, the wavelength of water is 438 nm

$\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}]$

Now placing these values to the above formula

So,

$= 438 \times \frac{1.333}{1.501}$

= 388.97 nm

We simply applied the above formula so that we can easily determine the wavelength of this light in benzene could come

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2 years ago

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Eduardwww [97]

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2 years ago

Luis and Aisha conducted an experiment. They exerted different forces on four objects. Their results are shown in the table.

lesya692 [45]

Answer:

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Explanation:

Objects Mass Force

1 10 kg 4 N

2 100 grams 20 N

3 10 grams 4 N

4 1 kg 20 N

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$a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{4}{10}\\\\a_1=0.4\ m/s^2$

Acceleration of object 2,

$a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{20}{0.1}\\\\a_2=200\ m/s^2$

Acceleration of object 3,

$a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{4}{0.01}\\\\a_3=400\ m/s^2$

Acceleration of object 4,

$a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{20}{1}\\\\a_3=20\ m/s^2$

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4 0

3 years ago

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