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chubhunter [2.5K]
3 years ago
8

As air rises, why do clouds form?

Physics
1 answer:
MissTica3 years ago
3 0

Answer:

C. the air cools to its dew-point temperature and condenses into liquid water

Explanation:

Clouds are formed when the air rises heated by terrestrial irradiation. As it warms, the air rises and rises until it reaches its dew point, which will be when the water vapor condenses on (dew) or ice crystals. These droplets, which have a spherical shape and measure between 0.004 and 0.1 mm, are in continuous motion when they are suspended in the air and when they are subjected to updrafts, so they collide with each other and group together. Depending on the atmospheric conditions, an increase in their thickness may occur so as to cause them to precipitate.

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A negatively charged rod is placed near two neutral metal spheres, as shown below. Which statements describe the charging method
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<h3>Answer;</h3>
  • <em>The spheres develop opposite charges. </em>
  • <em>Electrons move from Sphere A to Sphere B. </em>
  • <em>The spheres are charged through induction.</em>
<h3><u>Explanation;</u></h3>
  • <u><em>When a negatively charged rod is placed near two neutral metal spheres, the spheres will develop opposite charges, because the neutral metal spheres have both negative and positive charges. </em></u>From the basic law of electrostatics unlike charges attracts and like charges repel.
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What kind of scattering (Rayleigh, Mie, or non-selective) would you expect to be most important when radiation of the specified
oee [108]

Answer:

hello your question is not properly arranged attached below is the arranged table and solution

answer : attached table below

Explanation:

Given data:

02 molecules size = 10^-10m

smoke particles size = 0.3 mm

cloud droplets size = 20 mm

Rain droplets size = 3 mm

Attached below is a table showing the kind of scattering that is expected to occur at various wave lengths

Note : For Rayleigh scattering the wave particle is smaller than the wave length while for Non-selective scattering the wave particle is greater than the wavelength.

and  For Mie scattering the wavelength is the same as the wavelength.

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3 years ago
(a) In what direction would the ship in Exercise 3.57 have to travel in order to have a velocity straight north relative to the
shtirl [24]

Answer:

Direction of ship: 9.45° West of North

Ship's relative speed: 7.87m/s

Explanation:

A. Direction of ship: since horizontal of the velocity of boat relative to the ground is 0

Vx=0

Therefore, -VsSin∅+VcCos∅40°

Sin∅ = Vc/Vs × Cos 40°

Sin∅ = 1.5/7 ×Cos40°

Sin∅= 0.164

∅= Sin-¹ (0.164)

∅= 9.45° W of N

B. Ship's relative speed:

Vy= VsCos∅ + Vcsin40°

= 7Cos9.45° + 1.5sin40°

= 7×0.986 + 1.5×0.642

= 7.865

= 7.87m/s

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