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julia-pushkina [17]
3 years ago
8

If an airplane undergoes a displace-

Physics
1 answer:
PIT_PIT [208]3 years ago
4 0
The formula for velocity is distance divided by time, or d/t. The distance is 500 km and the time is 1.2 hours. 500/1.2 is 416.6 km/hr.
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Gravity on the surface of the moon is only 1/6 as strong as gravity on the Earth. What is the weight of a 19 kg object on the Ea
Dahasolnce [82]

The weight of anything in any place is

         (mass of the thing) x (acceleration of gravity in that place).

-- On Earth, the acceleration of gravity is about  9.807 m/s²

Weight of 19 kg of mass is  (19 kg) x (9.807 m/s²) =  <em>186.3 newtons</em>


-- On the Moon, the acceleration of gravity is about 1.623 m/s²

Weight of the same 19 kg of mass is  (19 kg) x (1.623 m/s²) = <em>30.8  newtons</em>

7 0
3 years ago
Which of the following is a circuit component whose function includes changing an open circuit to a closed circuit?
blondinia [14]

Answer:

<h2>B. Switch</h2>

Explanation:

<u>A device designed to open or close a circuit under controlled conditions is called a switch. The terms “open” and “closed” refer to switches as well as entire circuits. An open switch is one without continuity: current cannot flow through it.</u>

<h2><u>Hope this helps! Please consider marking brainliest!! </u></h2>
7 0
3 years ago
Read 2 more answers
An unstoppable object is heading right toward an unmovable object. What's going to happen?
marshall27 [118]

Answer:

In my opinion the unstoppable object will hit the unmovable object and stop but the wheels will still be rolling and trying to move but can't.

<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>
8 0
2 years ago
what would the mass be of an object that was moving at a velocity of 35 m/s and has a kinetic energy of 500j be?
bearhunter [10]

Answer:

0.816 kg

Explanation:

E_k=\frac{1}{2}mv^{2}\\

so m=\frac{2E_k}{v^2}=\frac{2\times500}{35^2}=0.816 kg

5 0
2 years ago
20 points and brainliest‼️‼️‼️‼️
Anastasy [175]

Answer:

0 N

Explanation:

Applying,

F = qvBsin∅................. Equation 1

Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.

From the question,

Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°

Substitute these values into equation 1

F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)

Since sin0° = 0,

Therefore,

F = 0 N

3 0
3 years ago
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