Answer:
puck decelerates due to the kinetic frictional force μk mg
Explanation:
given data
total distance = 12 m
coefficient of kinetic friction = 0.28
solution
we will apply equation of motion that is
v² - u² = 2 × a × s ................1
we know acceleration will be
a = 
Then we have
Force = mass × acceleration .................2
m × = -μk mg
The puck decelerates due to the kinetic frictional force μk mg
and frictional force is negative as it opposes the motion.
so we get initial velocity of the puck which is strike.
Answer:
the correct answer is A, North
Explanation:
The forces are vectors so they must be added vectorially.
The magnitude of the forces is the same, but not their direction, which is why they are different.
Analyze the situation presented
We have a force towards the North and another towards the South with the same magnitude, therefore these cancel each other out
We have a force towards the Northeast and another towards the Northwest, these can be decomposed into parts, one towards the North and another on the East-West axis, this last component is canceled, but the component towards the North is added.
In summary we see that the body accelerates towards the North
the correct answer is A
I might be wrong but I'm pretty sure It's B
It acquires a charge through electrons.
Hope this helps!!!^_~!!!
Answer:
y = 2.74 m
Explanation:
The linear thermal expansion processes are described by the expression
ΔL = α L ΔT
Where α the thermal dilation constant for concrete is 12 10⁻⁶ºC⁻¹, ΔL is the length variation and ΔT the temperature variation in this case 20ªc
If the bridge is 250 m long and is covered by two sections each of them must be L = 125 m, let's calculate the variation in length
ΔL = 12 10⁻⁶ 125 20
ΔL = 3.0 10⁻² m
Let's use trigonometry to find the height
The hypotenuse Lf = 125 + 0.03 = 125.03 m
Adjacent leg L₀ = 125 m
cos θ = L₀ / Lf
θ = cos⁻¹ (L₀ / Lf)
θ = cos⁻¹ (125 / 125.03)
θ = 1,255º
We calculate the height
tan 1,255 = y / x
y = x tan 1,255
y = 125 tan 1,255
y = 2.74 m
