Answer:
T = 4.905[N]
Explanation:
In order to solve this problem we must perform a sum of forces on the vertical axis.
∑Fy = 0
We have two forces acting only, the weight of the body down and the tension force T up, as the body does not move we can say that it is system is in static equilibrium, therefore the sum of forces is equal to zero.
![T-m*g=0\\T=0.5*9.81\\T=4.905[N]](https://tex.z-dn.net/?f=T-m%2Ag%3D0%5C%5CT%3D0.5%2A9.81%5C%5CT%3D4.905%5BN%5D)
Its simple use formuila ,
PV=nRT
n,R is constant as the both have same moles.
so,
(p1v1)/T1 = (p2v2)/T2
so, 128.53338kpa
Answer:
Therefore the escape velocity from Mar's gravity is
m/s.
Explanation:
Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.

Escape velocity
G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²
M= mass of Mars = 6.42×10²³ kg
R = Radius of the Mars = 3.40×10³m
The escape velocity does not depend on the velocity of a object.

m/s
Therefore the escape velocity from Mar's gravity is
m/s.